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mixas84 [53]
3 years ago
10

PLEASE HELP!!!!

Mathematics
2 answers:
irinina [24]3 years ago
7 0

Answer:

5

Step-by-step explanation:

52 + 28= 80

80-75=5

sertanlavr [38]3 years ago
6 0

Answer:

80 students

Step-by-step explanation:

52 + 28 = 80

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Marysya12 [62]
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5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

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Then find solutions,

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For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

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y_3=a-bi

the general solution has a form of,

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Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
4 years ago
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