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AnnZ [28]
3 years ago
7

A bee flies at 20 feet per second directly to a flower bed from its hive. HThe bee stays at the flower bed for 15 minutes, then

flies directly back to the hive at 12 feet per second. It is away from the hive fore 20 minutes total.
a. What equation can you use to find the distance of the flowerbed from the hive?
b. How far is the flowerbed from the hive?
Mathematics
1 answer:
Luden [163]3 years ago
3 0

we are given

A bee flies at 20 feet per second directly to a flower bed from its hive

so, forward speed is

s_f=20

flies directly back to the hive at 12 feet per second

so, backward speed is

s_b=12

It is away from the hive fore 20 minutes total

so,

total time = forward time + backward time + stay time

The bee stays at the flower bed for 15 minutes,

20 =tf+tb+15

t_f+t_b=5min

now, we can change it into seconds

t_f+t_b=5*60sec

t_f+t_b=300sec

(a)

we know that

distance between hive and flower bed will remain same

Let's assume

forward time =x

so,

t_f=x

t_b=300-x

we know that

distance = speed*time

d=s_f*t_f

now, we can plug values

d=20*x

d=s_b*t_b

now, we can plug values

d=12*(300-x)

both distances are same

20x=12*(300-x)

(b)

now, we can solve above equations and find x

20x=12*(300-x)

20x=3600-12x

add both sides 12x

20x+12x=3600-12x+12x

32x=3600

x=112.5

now, we can find distance

d=20*112.5

d=2250

so, distance between hive and flower bed is 2250 feet.........Answer


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