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Ratling [72]
2 years ago
13

a set of data has the following linear regression equation y = 1+3x what does the equation predict for a value of x=14?

Mathematics
1 answer:
trasher [3.6K]2 years ago
6 0
In this problem, you are simply going to input 14 for x in your equation.

y = 3x + 1
y = 3(14) + 1
y = 42+1
y = 43
This means, when x=14, y=43

Hope this helps!
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Factorise fully X^2 subtract 2x
anastassius [24]

Answer:

x(x-2)

Step-by-step explanation:

X^2-2x

x(x-2)

7 0
2 years ago
Can a variable be at the end of an equation
amm1812
Yes

Example
1+1 = x

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(a brainliest would be appreciated)
3 0
3 years ago
What's the pattern and what's the next term?
mojhsa [17]
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8 0
3 years ago
Store is selling Snapple’s for 1.75 and monsters for 2.50.yesterday their revenue was 147.75 and they sold 3 more monsters how m
navik [9.2K]

Answer:

The number of Snapple’s sold = 33

The number of monsters sold = 36

Step-by-step explanation:

Let us assume , the number of Snapple’s sold  = m

So, the number of monsters sold = Number of Snapple’s + 3  = m + 3

Now, the cost of 1 Snapple’s  = $1.75

So, the cost of m  Snapple’s = m x ( cost of 1 Snapple’s)  =  m x ($1.75)

= 1.75 m

Now, the cost of 1 monster  = $2.50

So, the cost of (m +3)  monsters = (m + 3 ) x ( cost of 1 monsters)  

=  (m+3) x ($2.50)  = 2.5 m + 7.5

So, total cost of  ( m Snapple’s + (m +3)  monsters) = 1.75 m + 2.5 m + 7.5

= 4.25 m + 7.5

Also, the total revenue generated  = $147.75

⇒ 4.25 m + 7.5  = $147.75

or, 4.25  m = 147.75  - 7.5  = 140.25

so, m = 140.25/4.25  = 33

Hence, the number of Snapple’s sold = m = 33

And, the number of monsters sold = m + 3  = 33 +  3  = 36

7 0
3 years ago
Which expression is equivalent to 7sqrtx^2/5sqrty^3? Assume y does not equal 0
Nezavi [6.7K]

Answer:

Option A) \bf{ x^{\frac{2}{7}}*y^{-\frac{3}{5}}}

Step-by-step explanation:

we have

\sf{\dfrac{\sqrt[7]{x^{2}}}{\sqrt[5]{y^{3}}}}

we know that

\sf{\sqrt[7]{x^{2}}=x^{\frac{2}{7}}}

\sf{\sqrt[5]{y^{3}}=y^{\frac{3}{5}}}

substitute in the expression

\sf{\dfrac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}=x^{\frac{2}{7}}*y^{-\frac{3}{5}}}

5 0
1 year ago
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