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Volgvan
2 years ago
12

PLEASE HELP THIS THE THE LAST TEST OF THE SEMESTER

Chemistry
1 answer:
Kazeer [188]2 years ago
3 0

Answer:

Its not balanced

Explanation:

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2 years ago
What is the order of reaction with respect to a and b for a reaction that obeys the rate law: rate = k[a]4[b]5?
spin [16.1K]

The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.

The order of reaction is equal sum of power of concentration of the each reactant present in the reaction  that obeys the rate law . The order of individual reactant or species present in the rate law is equal to the power of the of concentration of the respective species or reactant .

Example : If rate law is given as,

rate = k[a]^{4} [b]^{5}

The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.

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3 0
1 year ago
When 1 mol of a fuel burns at constant pressure, it exchanges-3452 kJ of heat and does-11 kJ of workon the surroundings. What ar
Degger [83]

Answer:-3463 kJ and -3452kJ

Explanation:

ΔU is the change in internal energy of a system and its formula is;

ΔU = q + w

Where q represents heat transferred into or out of the system. Its value is positive when heat is transfer into the system and negative when heat is produced by the system.

W represents the work done on or by the system. Its value is positive when work is done on the system and negative when it is done by the system.

For the system in this question, we see that it produces heat which means heat is transferred out of the system, therefore the value of q is negative, it can also be seen that work is done by the system which means that w is also negative.

Therefore,

ΔU = -q-w

ΔU = -3452 kJ – 11kJ

= - 3463kJ

ΔH is the change in the enthalpy of a system and its formuls is;

ΔH = ΔU + Δ(PV)

By product rule Δ(PV) becomes ΔPV + PΔV

At constant pressure ΔP = 0. Therefore,

ΔH = -q-w + PΔV

w is equals to PΔV, So:

ΔH = -q

ΔH = -3452kJ

6 0
3 years ago
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