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3 years ago

PLEASE HELP THIS THE THE LAST TEST OF THE SEMESTER

Chemistry

1 answer:

Kazeer [188]3 years ago

3 0

Answer:

Its not balanced

Explanation:

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How many kilojoules of heat are released when 32.0 g of NaOH are dissolved in water? (The molar heat of solution of NaOH is –445

Katen [24]

The energy release when dissolving 1 mol of NaOH in water is 445.1 kJ
the mass of NaOH to be dissolved is 32.0 g
The number of NaOH moles in 32.0 g - 32.0 g / 40 g/mol = 0.8 mol
the energy released whilst dissolving 1 mol of NaOH - 445.1 kJ
when dissolving 0.8 mol - the energy released is 445.1 kJ/mol x 0.8 mol
therefore heat released is - 356.08 kJ
answer is -356.08 kJ

6 0

3 years ago

Read 2 more answers

Exercise 2

Brums [2.3K]

Answer:

1. Reuse

2.Recycle

3.Reuse

4.Reduce

5.Recycle

Explanation:

Yun lang po ang alam ko.

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3 years ago

Boiling Point is the __________. *

sergiy2304 [10]

Boiling point is the temperature at which a liquid boils and turns to a gas.

Hope this helps!! (:

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2 years ago

How many liters of carbon dioxide will be produced at STP if 3.56 g calcium carbonate reacts completely with carbon dioxide? CaC

sp2606 [1]

Answer:

V = 0.798 L

Explanation:

Hello there!

In this case, for this gas stoichiometry problem, we first need to compute the moles of carbon dioxide via stoichiometry and the molar mass of starting calcium carbonate:

$3.56gCaCO_3*\frac{1molCaCO_3}{100gCaCO_3} *\frac{1molCO_2}{1molCaCO_3} =0.0356molCO_2$

Next, we use the ideal gas equation for computing the volume, by bearing to mind that the STP conditions stand for a pressure of 1 atm and a temperature of 273.15 K:

$PV=nRT\\\\V=\frac{nRT}{P}\\\\V=\frac{0.0356mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm} \\\\V=0.798L$

Best regards!

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3 years ago

What is the conversion factor for in^3 to cm^3

DochEvi [55]

You multiply by 16.3871

5 0

2 years ago