The answer is "32.9 meq/liter".
1875ml = 1875 / 1000 = 1.875ml
mass of magnesium = 24.305 g
0.750 g Mg²+ x 1 mole Mg²⁺/24.305 g x 2 equivalents/mole
= 0.617 equivalents0.0617 eq x 1000 meq/eq = 61.7 meq37.4 meq/1.875 L = 32.9 meq/liter
The enthalpy change for the formation step of this intermediate is 136 kJ/mol.
<h3>What is the enthalpy?</h3>
The enthalpy of reaction can be obtained from the enthalpies of formation of the species involved. The enthalpy of reaction is the heat evolved or absorbed in a reaction.
Thus, the enthalpy change for the formation step of this intermediate is 4 * 34 kJ/mol = 136 kJ/mol.
Learn more about enthalpy change:brainly.com/question/4526346
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