Answer:
All of them affect the DNA
Explanation:
Chemicals are compounds that can pass through cell membranes and modificate the DNA, elevated temperatures can denaturalize the cell and therefore damage the DNA, ionizing radiation can pass through cell organelles and reach the nucleus affecting the DNA, and viruses inject its DNA into the genome and modify it.
If it is assumed that there are only two isotopes then the percent abundance needs to add up to 100%
100-35= 65%
The second isotope will have a 65% abundance.
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8.98
×
N
A
cobalt atoms
Explanation:
N
A
,
Avogadro's number
specifies
6.0221
×
10
23
individual particles. It is simply another collective number like a dozen, or a score, or a gross.
N
A
has the property that
6.0221
×
10
23
individual cobalt atoms has a mass of
58.93
⋅
g
. How did I know that? Did I have it memorized?
So the quantity is
≈
54
×
10
23
cobalt atoms.
Answer:
1. 12.6 moles
2. 8.95 moles
3. 2A + 5B → 3C
4. 48 moles
Explanation:
1. 2Fe + 3Cl₂ → 2FeCl₃
We assume the chlorine in excess. Ratio is 2:2
2 moles of Fe, can produce 2 moles of chloride
12.6 moles of Fe will produce 12.6 moles of chloride.
2. 2Fe + 3Cl₂ → 2FeCl₃
For the same reaction, first of all we need to convert the mass to moles:
500 g . 1mol / 55.85 g = 8.95 mol
As ratio is 2:2, the moles we have are the same, that the produced
4. The reaction for the combustion is:
2C₂H₆ (g) + 7O₂ (g) → 4CO₂ (g) + 6H₂O (l)
We assume the oxygen in excess.
Ratio is 2:6, so 2 mol of ethane produce 6 moles of water
Therefore 16 moles of ethane may produce (16 .6) / 2 = 48 moles
<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is HCl.
are the n-factor, molarity and volume of base which is 
We are given:

Putting values in above equation, we get:

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

Molarity of solution = 0.011 M
Volume of solution = 36.0 mL
Putting values in above equation, we get:

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.
Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles
Hence, the moles of hydroxide ions present in the sample is 0.0008 moles