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SVEN [57.7K]
3 years ago
12

If the bathtub holds a total of 46.2 gallons, how many minutes would it take to fill the entire tub? Write an equation in one va

riable to help you
solve the problem. The variable represents the unknown time in minutes.

BI y Xx Font Sizes - AA EI E

N
Mathematics
1 answer:
sergejj [24]3 years ago
8 0

Answer:

It will take 2.8 minutes

Step-by-step explanation:

Given

x \to Minutes

y \to Gallons

See attachment for complete question

Required

Time to fill the tube with 46.2 gallons

The attached table is a represents a direct proportional relationship between x and y.

This relationship is:

y = kx

Where k is the constant of proportionality.

When (x,y) = (1,16.5), we have:

16.5 = k*1

16.5 = k

k=16.5

So, we have:

y = kx

y = 16.5x

To calculate the required time to fill 46.2 gallons, we make x the subject

x = \frac{y}{16.5}

Where

y =46.2

x = \frac{46.2}{16.5}

x = 2.8

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1 year ago
At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T
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Answer:

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

\text{Area of circle}=\pi r^2, where r represents radius of the circle.

\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2

\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

Therefore, the exact area of the side walk is 40 \pi\text{ m}^2

To find the approximate area of side walk let us substitute pi equals 3.14.

\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Therefore, the approximate area of the side walk is 125.6\text{ m}^2.

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3 years ago
How do you write 100 as a power of 10
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