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dlinn [17]
3 years ago
15

Calculate 4 1/5 x 1/3 - 1 1/4​

Mathematics
1 answer:
Marat540 [252]3 years ago
6 0

Answer:

3/20

Step-by-step explanation:

4 1/5 x 1/3 =

<em><u>1 2/5</u></em>

1 2/5 - 1 1/4 =

<u><em>3/20</em></u>

Have a nice day :)

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12÷36.2 I need help because I'm getting a wrong answer I think ​
raketka [301]

Answer:

0.331491713 but can convert to 60/181

Step-by-step explanation:

7 0
2 years ago
A graph is shown below
Rina8888 [55]
Ahem, mandy wheres the GRAPH>?
7 0
4 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
for his phone service, Chua pays a monthly fee of 25, and he pays an additional $0.05 per minute of use. the least he has been c
postnew [5]

Inequalities

Chua pays a monthly fee of $25 for his phone service, plus $0.05 per minute of use.

Let M = number of minutes Chua uses the phone service.

His monthly cost for the phone service is:

C = 25 + 0.05M

The least he has been charged in a month is $89.40. If we want to know the number of minutes he used the service in that month, then we must solve the inequality:

25 + 0.05M ≥ 89.40

Subtracting 25:

0.05M ≥ 89.40 - 25

Operating:

0.05M ≥ 64.40

Dividing by 0.05:

M ≥ 64.40 / 0.05

M ≥ 1288

He has used his phone service at least for 1288 minutes in a month

8 0
1 year ago
A​ 2.5-meter piece of framing lumber has been used to cut a piece 1.65 meters long. How much of the original piece of lumber​ re
mrs_skeptik [129]

Answer:

0.85 of the original piece of lumber remains.

Step-by-step explanation:

Well, this lumber piece of lumber started as 2.5 meters long. Then, a 1.65 meter piece was cut off of it. All we need to do is subtract.

2.5 - 1.65 =

2.50 - 1.65 = 0.85.

Therefore, 0.85 of the original piece of lumber remains.

Hope this helps! :)

7 0
3 years ago
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