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Artemon [7]
3 years ago
13

How do I solve these problems?

Mathematics
2 answers:
dalvyx [7]3 years ago
6 0

Answer:

1.) The 1ˢᵗ three term is (-32), (-7) and 18

2.) The 1ˢᵗ three term is 127, 106 and 85

Step-by-step explanation:

<h2>1.)</h2>

Here,

First Term = a₁ = - 32

Common Difference = (d) = 25

Now, For 1ˢᵗ three term,

<u>n = 1</u>

a₁ = - 32

<u>n = 2</u>

<em>aₙ = a + (n - 1)d</em>

a₂ = (-32) + (2 - 1) × 25

a₂ = (-32) + 1 × 25

a₂ = (-32) + 25

a₂ = -7

<u>n = 3</u>

<em>aₙ = a + (n - 1)d</em>

a₃ = (-32) + (3 - 1) × 25

a₃ = (-32) + 2 × 25

a₃ = (-32) + 50

a₃ = 18

Thus, The 1ˢᵗ three term is (-32), (-7) and 18

<h2>2.)</h2>

Here,

First Term = a₁ = 127

Common Difference = (d) = -21

Now, For 1ˢᵗ three term,

<u>n = 1</u>

a₁ = 127

<u>n = 2</u>

<em>aₙ = a + (n - 1)d</em>

a₂ = 127 + (2 - 1) × (-21)

a₂ = 127 + 1 × (-21)

a₂ = 127 - 21

a₂ = 106

<u>n = 3</u>

<em>aₙ = a + (n - 1)d</em>

a₃ = 127 + (3 - 1) × (-21)

a₃ = 127 + 2 × (-21)

a₃ = 127 - 42

a₃ = 85

Thus, The 1ˢᵗ three term is 127, 106 and 85

<u>-TheUnknownScientist</u>

densk [106]3 years ago
3 0
A is the first value of the sequence, then you increase or decrease by d each time
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