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Angelina_Jolie [31]
3 years ago
15

I have 120 blocks. Each block is one of 2 different materials, 3 different colors, 4 different sizes and 5 different shapes. No

two blocks have exactly the same all four properties. I take two blocks at random. What is the probability that these two blocks have exactly two of these four properties the same?
Mathematics
1 answer:
ira [324]3 years ago
4 0

Answer: 0.54

Step-by-step explanatio;

We would have three in common out of 4 characteristics (4 out of 4 is not possible). There are 4 possible ways to share 3 out of 4 characteristics.

Denoting the characteristics as {M,C,Si,Sh} so P(B2={1,1,1,0}|B1={1,1,1,0}) is the probability that box 2 shares its first three characteristics with box 1 given that box one has characteristics

We now have

P(B2 has 3 elements in common with B1)=P(B2={1,1,1,0}|B1={1,1,1,0})xP(B1={1,1,1,0})+P(B2={1,1,0,1}|B1={1,1,0,1})xP(B1={1,1,0,1})+P(B2={1,0,1,1}|B1={1,0,1,1})xP(B1={1,0,1,1})+P(B2={0,1,1,1}|B1={0,1,1,1})xP(B1={0,1,1,1})

P(B2 has 3 elements in common with B1)=(4x5x24+3x4x30+2x3x40+1x2x60)1120x119= 0.084

which is close enough to the value from the simulation code (modified to count the number of 3-ties)

Now, I use the same reasoning to compute:

P(B2 has 2 or more elements in common with B1)=(19x20x6+11x12x10+9x10x12+14x15x8+7x8x15+5x6x20)1120x119= 0.54

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svlad2 [7]

Option D

The percentage increase of the area  of the building space is 34 %

<em><u>Solution:</u></em>

A company is expanding its building area from 11,000 square feet to 14,740 square feet

To find: Percentage Increase

<em><u>The percent increase is given by formula:</u></em>

\text{Percent increase } = \frac{\text{Final value - Initial value}}{\text{Initial value}} \times 100

From given,

Initial value = 11000

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<em><u>Substituting we get,</u></em>

Percent\ Increase = \frac{14740-11000}{11000} \times 100\\\\Percent\ Increase = \frac{3740}{110}\\\\Percent\ Increase = 34

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3 years ago
99 students choose to attend one of three after school activities: football, tennis or running.
nordsb [41]

Answer:   \dfrac{49}{99}

<u>Step-by-step explanation:</u>

There are 61 boys --> 38 girls

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\large\boxed{\begin{array}{l|cc||c}&\underline{Boys}&\underline{Girls}&\underline{Total}\\Football&14&5&19\\Tennis&26&5&31\\\underline{Running}&\underline{\quad 21\quad}&\underline{\quad 28\quad}&\underline{\quad 29\quad}\\Total&61&38&99\end{array}}

Total running = 21 boys + 28 girls = 49

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\dfrac{\text{Total running}}{\text{Total students}}=\large\boxed{\dfrac{49}{99}}

3 0
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Answer:

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Step-by-step explanation:

21 ÷ 30 = 0.7 = 70%

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