7/8 = 87.5%
I'm guessing it is meant to say round to the nearest 10th of a percent
If the question actually says something different comment so i can fix it
Answer:
Connect the intersections of the diameters and the circle with a segment
Step-by-step explanation:
Assuming the construction creates two orthogonal diameters, their ends will be the vertices of the inscribed square. Connecting them with segments in order around the circle will create the square.
The answer should be1200 feet
Answer:
C and D
Step-by-step explanation:
using the rules of exponents
A
= ![\sqrt[7]{125^3}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7B125%5E3%7D)
≠ ![\sqrt[3]{125^7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%5E7%7D)
B
(
)^7 = 
≠ 
C
(
)^5 = 
← correct
D
(
)^9 = 
← correct
<span>The name of the shape graphed by the function r ^ 2 = 9
cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a
plane curve with a feature shape which consists of two loops that meet at a
central point. The curve is also sometimes called as the lemniscate of
Bernoulli. </span>
Explanation:
The
period of coskθ is 2π/k. In this case, k = 2 therefore the
period is π.
r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily
one period can be chosen as θ ∈
[0, π] wherein cos 2θ ≥0.
As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.
Also,
as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the
vertical θ = π/2
A
Table for half period [0,π4/] is
adequate for the shape in Quarter1
Use symmetry for the other three quarters:
(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>
