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beks73 [17]
3 years ago
9

The temperature at 8 a.m. was -21.3. At 11 a.m. it was -17.2. What is the difference in these two temperatures?

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0
Subtract those two numbers
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N independent random samples of 10 men and 10 women in a coed basketball league, the numbers of points scored per season are giv
faltersainse [42]

Answer:

Step-by-step explanation:

Hello!

a)

To compare both datasets I've made a box plot for them.

The yellow one belongs to the points scored by the men and the green one is for the points scored by the women.

Women: The box seems symmetrical, the median and the mean (black square) are almost the same. The whiskers are almost the same length, you could say that in general the points scored by the women have a symmetrical distribution.

Men: The box looks a little skewed to the right, the median is closer to the 1st quantile and the mean is greater than the median. The whiskers are the same length, in general the distribution seems almost symmetrical.

b)

As you can see in the box plot  the median and mean of the points scored by the women are almost the same. Using the data I've calculated both values:

Me= 24.50

X[bar]= 23.80

The median divides the sample in halves (50-50),  it shows you where the middle of the distribution is.

The average shows you the value that centers the distribution, meaning, it is the value around which you'll find most of the data set. It summarizes best the sample information and therefore is a better measure of center.

c.

As you can see in the box plots, there are no outliers in both distributions.

An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.

Considering the 1st quartile (Q₁), the 3rd quartile (Q₃) and the interquartile range IQR, any value X is considered an outlier if:

X < Q₁ - 1.5 IQR

X > Q₃ + 1.5 IQR

Or extreme outliers if:

X < Q₁ - 3 IQR

X > Q₃ + 3 IQR

For the women data set:

Q₁= 17; Q₃= 30; IQR= 30 - 17= 13

Lower outliers: X < Q₁ - 1.5 IQR= 17-1.5*13= -2.5 ⇒ The minimum value recorded is 03, so there are no outliers.

Upper outliers: X > Q₃ + 3 IQR= 30 + 1.5*13= 49.5 ⇒ The maximum value registered is 41, so there are no outliers.

I hope this helps!

6 0
3 years ago
What value of n makes the equation true?
In-s [12.5K]

Answer:

-0.7

Step-by-step explanation:

First do 3.2-1.8= 1.4. So now we know that -2n=1.4. Next you solve for n to get the answer of -0.7 with your answer of the third option.

4 0
3 years ago
6y+5(2y+3y)+0+0+0+0+0+0
BARSIC [14]

Answer: 31y

Step-by-step explanation: Factor the expression and simplify. Could I please have brainliest?

5 0
3 years ago
Read 2 more answers
If f(x)=x+7 and g(x)=<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%20-%2013%7D%20" id="TexFormula1" title=" \frac{
Sergio [31]
Hi,

f(x)=x+7\\&#10;&#10;g(x)= \dfrac{1}{x-13} \\&#10;&#10;(fog)(x)=f(g(x))=f(\dfrac{1}{x-13})=\dfrac{1}{x-13}+7\\&#10;&#10;&#10;
Domain of (fog)(x) is R \ {13} =(-oo 13[ U ]13 +oo)

8 0
3 years ago
The area of a triangle is 92 square inches. The base is 23 inches. What is the height in inches? Do not include units in your an
postnew [5]

Answer:

34,5 ?? I am not good at this but I did 92-23 that's 69 ÷ 2 = 34.5 ?

3 0
3 years ago
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