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beks73 [17]
3 years ago
9

The temperature at 8 a.m. was -21.3. At 11 a.m. it was -17.2. What is the difference in these two temperatures?

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0
Subtract those two numbers
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The volume of the triangular prism is 54 cubic units.What is the value of x?
nadezda [96]

Answer:

x=3

Step-by-step explanation:

the volume of the prism with triangular base is 54 unit³

The base is a triangle with,  base i.e 4 units  and  height i.e x units

Also,  height of the prism = 3x

So, volume of the prism is,

And

,

Area_{Triangle}=\dfrac{1}{2}\times base\times Height_{Triangle}=\dfrac{1}{2}\times 4\times x=2x\ unit^2

Then,

V_{Prism}=2x\times 3x=6x^2

As the volume is given as 54 unit³, hence

6x²=54

x²=9

x=3

6 0
3 years ago
Sketch a model to show how to combine the following fractions: 4/3 + 2/3 =
DerKrebs [107]
4/3 + 2/3= (4+2)/3= 6/3= 2
3 0
3 years ago
Read 2 more answers
Convert 17.42 m to customary units. A.57'-17/8" B. 36-10 1/2" C. 442 1/2" D. 367/8" E. None of these answers is reasonable.
Allushta [10]

Answer:

E. None of these answers is reasonable.

Step-by-step explanation:

Customary units are inches, feet, yards, and miles.

Since,

1 foot = 0.3048 meters,

⇒ 1 meter = \frac{1}{0.3048} feet,

17.42 meters = \frac{17.42}{0.3048} feet

=\frac{174200}{3048}\text{ feet}

=57\frac{ 464}{3048}\text{ feet}

=57\frac{58}{381}\text{ feet}

Now, 1 feet = 12 inches,

⇒ \frac{58}{381} feet = \frac{12\times 58}{381} inches

= \frac{232}{381}\text{ inches}

Hence,

17.42 meters = 57\text{ feet }\frac{232}{381}\text{ inches}

= 57' 232/127''

That is, None of these answers is reasonable.

8 0
3 years ago
The bill at a restaurant is $160. You leave a 20% tip. What is your total
mash [69]
$192 because its plus tip.
8 0
3 years ago
A principal of ​$6000 is invested in an account paying an annual rate of 5​%. Find the amount in the account after 4 years if th
astra-53 [7]

Solution :

Given :

Principal amount deposited, P = $ 6000

Rate of interest, r = 5%

Number of years, t = 4 years

When the deposited amount is compounded semiannually, i.e. n = 2

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{2}\right)^{2 \times 4}$

$FV = 6000 \times (1.025)^8$

       = 6000 x 1.2184

        = 7310.4

Therefore, after 4 years there will be $ 7310.4 in the amount when compounded semi annually.

When the deposited amount is compounded quarterly, i.e. n = 4

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{4}\right)^{4 \times 4}$

$FV = 6000 \times (1.0125)^{16}$

       = 6000 x 1.219889

        = 7319.334

Therefore, after 4 years there will be $ 7319.334 in the amount when compounded quarterly.

When the deposited amount is compounded monthly, i.e. n = 12

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{12}\right)^{12 \times 4}$

$FV = 6000 \times (1.0041667)^{48}$

       = 6000 x 1.22089

        = 7325.34

Therefore, after 4 years there will be $ 7325.34 in the amount when compounded monthly.

8 0
3 years ago
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