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Lapatulllka [165]
3 years ago
14

Cirrus clouds form more than 6,000 meters above earth. Write an inequality to represent h, the height in meters, of cirrus cloud

s.
(Remember, you need to hold Shift to get the inequality symbols on your keyboard.)



If you did not read carefully, you must use h as the variable in your inequality, or it will be marked incorrect. Plssss help!! 20 points1!!!
Mathematics
1 answer:
tangare [24]3 years ago
4 0

Answer:

no lo se no se mucho de ingles

Step-by-step explanation:

lo siento

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-c>-19 solve the inequality
Katen [24]

Answer: c < 19

Step-by-step explanation:

3 0
3 years ago
Find the area of the figure with Heron’s formula
Anna11 [10]

Answer:

735 cm²

Step-by-step explanation:

The figure is a trapezium .The area of the triangle section can be calculated using the Heron's formula.

The other part of the figure will be a square of sides 21 cm by 21 cm

<u>Area of the square section</u>

Area = l²

Area = 21* 21 = 441 cm²

<u>Area of the triangle using Heron's formula</u>

Sides of the triangle are ;

a= 28 cm

c= 35 cm

b = 21 cm -----height of the trapezium

The Heron's formula is given as;

A=\sqrt{s( s-a)(s-b )(s-c )}

where s is half the perimeter of the triangle

Perimeter of the triangle is given as ;

P= 35 + 28 + 21 =84 cm

s= 84/2 = 42 cm

A=\sqrt{42*(42-21 )*(42-35 )*(42-28 )} \\\\A=\sqrt{42*(21 )*(7 )*( 14)} \\\\A=\sqrt{86436} \\\\A=294\\\\

Total area = 294 + 441 = 735 cm²

7 0
3 years ago
How to put 33 into 4:7
Tema [17]
4+7 = 11
so
33 / 11 = 3

4 x 3 = 12
7 x 3 = 21

so answer
4:7 = 12:21
4 0
3 years ago
I will mark brainest if it is right<br> 1. x+20 = 11x + 30<br> x=
Sveta_85 [38]

Answer:

Step-by-step explanation:

x+20=11x+30  minus x from both sides

20=10x+30  minus 30 from both sides

-10=10x  divide by 10

x= -1

5 0
3 years ago
Read 2 more answers
Quadratics: Writing Vertex Form, Algebra 1- Mrs. Daniel, Kuta Software
Oliga [24]
Vertex form is given by:
y=a(x-h)^2+k
where the vertex is (h,k)
7. (h,k)=(-4,1)
plugging in the equation we get:
y=a(x+4)^2+1
but substituting (0,2) in the equation and solving for a we get:
2=a(0+4)^2+1
a=1/16
hence:
Answer: y=1/16(x+4)^2+1

8] 
(h,k)=(2,-4)
thus
y=a(x-2)^2-4
plugging point (3,0) in the eqn and solving for a we get
0=a(3-2)^2-4
0=a-4
a=4
hence;
Answer: y=a(x-2)^2-4

9] (h,k)=(3,3)
thus;
y=a(x-3)^2+3
plugging (2,2) in the equation we get:
2=a(-1)^2+3
a=-1
thus;
Answer: y=-1(x-3)^2+3

10] (h,k)=(-1,-1)
y=a(x+1)^2-1
plugging (0,-3) in the equation and solving for a we get:
-3=a(1)^2-1
a=-2
thus
Answer: y=-2(x+1)^2-1

11] (h,k)=(1,2)
y=a(x-1)^2+2
plugging (0,4) in the equation and solving for a we get:
4=a(-1)^2+2
a=2
thus
y=2(x-1)^2+2

12] (h,k)=(3,-2)
y=a(x-3)^2-2
plugging (2,0) and solving for a we get:
0=a(2-3)^2-2
a=2
thus
t=2(x-3)^2-2
6 0
3 years ago
Read 2 more answers
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