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kvasek [131]
2 years ago
10

What is the completely factored form of x^4y- 4xły - 5y?

Mathematics
1 answer:
tamaranim1 [39]2 years ago
3 0
If you mean by completely factored form of x^4y - 4x2y - 5y

Then the answer is y (x^2 - 5) (x^2 + 1)
You might be interested in
A theatre has seats arranged in rows of 24, 382 people attend a show at the theatre. What is the smallest number of rows that is
kipiarov [429]

Answer:

A minimum of 16 rows are needed

Step-by-step explanation:

Here, we want to calculate the number of rows minimum that could seat 382 people in rows of 24 seats.

Mathematically, what we need to do here is to make a division.

We shall divide the number of people by the number of seats in a row so that we can get the number of rows needed.

Mathematically, that would be; 382/24 = 15 22/24

We are looking at a minimum number.

So we can see that 15 rows will be filled, with an extra 22 seats in the next row leaving only 2 seats in the next row unoccupied.

So we can see that the minimum number of rows required is 16 rows

3 0
3 years ago
−7=y7 please help me out
Yuri [45]

Answer:

Step-by-step explanation:

y=-1

7 0
2 years ago
Read 2 more answers
I will give brainliest to the first to answer
bonufazy [111]

Answer:

2/6 = 1/3

8/1 = 8

2/4 = 4/8

2/8 = 1/4

4/4 = 1

Step-by-step explanation:

2/2 = 1 and 6/2 = 3 so that would make the equivalent fraction 1/3

for 8/1 it is the same as just 8

2*2 = 4 and 4*2 = 8 so that would make the equivalent fraction 4/8

the same goes for 2/8 which is 1/4

and 4/4 is just 1  

PLEASE RATE!! I hope this helps!!

If you have any questions comment below

5 0
2 years ago
Read 2 more answers
Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
2 years ago
|8m| = 104 absolute value
DENIUS [597]

Answer:

m=13

Step-by-step explanation:

Ok

l8ml=104

8m=104

⁻⁻⁻  ⁻⁻⁻

8        8

m=13

6 0
3 years ago
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