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3 years ago

Hi how are you ! What is this answer ?

Mathematics

2 answers:

Hitman42 [59]3 years ago

8 0

The answer is U=90 degree

sveticcg [70]3 years ago

4 0

Answer:

Step-by-step explanation:

take angle U as reference angle

using sine rule

sin U=opposite /hypotenuse

sin U=42/42

sin U=1

sin 90=1

therefore angle U=90 degree

You might be interested in

Find the equation of the line that passes through (−4, 8) with slope −3. Write in slope-intercept form. F y = – 3x – 4 G y = – 4

storchak [24]

Answer: y=-3x-4

Step-by-step explanation:

Since we know slope, we can plug it into slope-intercept form to find the y-intercept by using the given points,

y=-3x+b

8=-3(-4)+b

8=12+b

b=-4

Now that we know the y-intercept, we can complete the slope-intercept form.

y=-3x-4

8 0

3 years ago

How do you find the median of these numbers $17.49, $11.29, $16.89, $11.79?

luda_lava [24]

Good morning, kid. It's quite easy.

The median is the middle number in a set after you place them least to greatest:

$11.29, $11.79, $16.89, $17.49

Well, since the numbers in the set are even, meaning there are only 4 numbers, we pick out the 2 middle numbers which would be, $11.79 and $16.89. Find the average (add them and divide by 2) and you'll get the median.

$11.79 + $16.89 = $28.68/2 = $14.34
Thus, the median is: $14.34

6 0

4 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height

Ilia_Sergeevich [38]

Answer:

$\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s$

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

$\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}$

From this point on, you have two possibilities, either you find each individual $y_{f}, y_{0}, t_{f}, t_{0}$ and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

$t_{f}-t_{0}=\Delta t$

and we also know that:

$t_{f}=t_{0}+\Delta t$

in order to find the final position, we can substitute this final time into the function, so we get:

$y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}$

so we can rewrite our formula as:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}$

$y_{0}$ will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

$y_{0}=29t-22t^{2}$

$y_{0}=29(1)-22(1)^{2}$

$y_{0}=7ft$

we can substitute it into our average velocity equation:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}$

and we also know that the initil time will always be 1, so we can substitute it as well.

$\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}$

so we can now simplify our formula by expanding the numerator:

$\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}$

$\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}$

we can now simplify this to:

$\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}$

Now we can factor Δt to get:

$\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}$

and simplify

$\overline{v}=-15-22\Delta t$

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

$\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s$

$\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s$

$\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s$

$\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s$

5 0

3 years ago

Does this graph represent a function? Why or why not?

malfutka [58]

Answer:

Yes.

Step-by-step explanation:

It is a function because it passes the vertical line test. Each x-value has just one y-value. If the relation had any x-values that had several y-values, it would just be a relation. But this one is a function.

Hope this helps!

6 0

3 years ago

A circular plot with a 160 foot diameter is watered by a spray irrigation system. To the nearest square foot, what is the area t

Anuta_ua [19.1K]

A circular plot is watered by a sprinkler that rotates through it. The sprinkler only rotates through a semi-circle, or half of the whole circle.

Area of a circle: A = pi x r^2

r = 160 / 2 = 80

A = pi x 80^2

A = 6400pi / 2 = 3200pi

3200pi = 10053.0965

The area water is approximately 10,053 ft^2.

Hope this helps!! :)

4 0

3 years ago