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Thepotemich [5.8K]

4 years ago

5

A rectangular backyard has dimensions represented by the expressions shown. which expression represents the perimeter of the bac

kyard?
A. 4x-2
B. 3x+2
C. 6x^2+4
D. 6x+4

1 answer:

tester [92]4 years ago

6 0

Answer:

Do you have the figure Friend?

If yes please attach it too!

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A huge suspended LED screen is the centerpiece of The Place, a popular mall in Beijing, China. Find the length and width of a si

dusya [7]

The length and width of the similar rectangular screen are 110 meters and 35 meters respectively.

<u>SOLUTION: </u>

Given, A huge suspended LED screen is the centerpiece of The Place, a popular mall in Beijing, China.

We have to find the length and width of a similar rectangular screen

We are also given that the length is 5 meters more than 3 times its width,

Let width of rectangle be "b" meters, the its length will be 5 + 3b meters

And, the viewable area is 3,850 square meters.

$\begin{array}{l}{\text { So, area }=3850} \\\\ {\text { Length } \times \text { width }=3850} \\\\ {(5+3 b) \times b=3850} \\\\ {5 b+3 b^{2}=3850} \\\\ {3 b^{2}+5 b-3850=0}\end{array}$

Now,let us use quadratic formula:

$\begin{array}{l}{\mathrm{x}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}} \\\\ {\text { Then, } \mathrm{b}=\frac{-5 \pm \sqrt{5^{2}-4 \times 3 \times(-3850)}}{2 \times 3}}\end{array}$

$\begin{array}{l}{\mathrm{b}=\frac{-5 \pm \sqrt{25+46200}}{6}} \\\\ {\mathrm{b}=\frac{-5 \pm \sqrt{46225}}{6}} \\\\ {\mathrm{b}=\frac{-5 \pm 215}{6}} \\\\ {\mathrm{b}=\frac{-5+215}{6} \text { or } \frac{-5-215}{6}} \\\\ {\mathrm{b}=\frac{210}{6} \mathrm{or} \frac{-220}{6}}\end{array}$

Neglect negative values as width can’t be negative

$b=\frac{210}{6}=35$

so, width = 35 meters, then length = 5 + 3(35) = 5 + 105 = 110 meters

hence, the length and width of the similar rectangular screen are 110 meters and 35 meters respectively.

3 0

3 years ago

IF I BUY A BOOK FOR $30. AND ITS MARKED DOWN 20%. HOW MUCH IS IT MARKED DOWN?

nalin [4]

The price would end up being $24
10% of 30 would be $3 then you double it to find 20% so it would end up being $6 off

8 0

3 years ago

8s + 9 = 7s + 6 <br>s= ?

denis-greek [22]

Answer:

s = -3

Step-by-step explanation:

8s + 9 = 7s + 6

Subtract 7s from each side

8s-7s + 9 = 7s-7s + 6

s+9 = 6

Subtract 9 from each side

s + 9-9 = 6-9

s = -3

7 0

3 years ago

Read 2 more answers

In the text box below write a brief summary highlighting some of the similarities and differences you noticed about these functi

otez555 [7]

About what functions? You should take a photo of your work!

4 0

3 years ago

if the mean of a population is 250 and its standard de- viation is 20, approximately what proportion of obser- vations is in the

Anton [14]

Observed proportions (relative frequencies) from a sample are statistics that can be used to estimate probabilities.

a) Thre is 99.73% proportion of observations is in between 190 and 310 .

b)there is 95.44% proportion of observations is in between 210 and 290 .

We have given that,

Mean of population, μ = 250

standard deviations, σ = 20

we have to calculate proportion of observations in the given interval pair.

a) pair of values are 190 and 310

Using Z-score formula,

Z =( x - μ) /σ

=> Z = (190 - 250) / 20 = -3

Similarly, Z = (310 - 250)/20 = 3

So, -3 < z < 3 and from Z score we found p-value

P(190<X<310) = P( 190-u/sd < X-u/sd < 310-u/sd)

= P( X< 310 ) - P(X<190) = P(Z < 3) - P( Z< -3 )

=0.99865 - 0.00135 0.9973 = 99.73%

b) pair is 210 and 290

Z-Score = (210-250)/20 = -2

Z-score = (290-250)/20 = 2

so, -2 < z < 2

From Z score we found p-value

P(210<X<290) = P(X<290) - P(X<210)

= P(Z< 2) - P(Z< -2)

= 0.9772 - 0.0228 = 0.9544 = 95.44%

So, the required proportion are 99.73% and 95.44% proportion of observations in each given pair.

To learn more about Proportion value , refer:

brainly.com/question/19131394

#SPJ4

Complete question:

If the mean of a population is 250 and its standard deviation is 20, approximately what proportion of observations is in the interval between each pair of values? a 190 and 310 b. 210 and 290.

6 0

1 year ago