Answer:
8.33
Step-by-step explanation:
Answer:
A) 0
Step-by-step explanation:
When x is divided by 11, we have a quotient of y and a remainder of 3
x/11 = y + 3
x = 11y + 3 ........(1)
When x is divided by 19, we have a remainder of 3 also
x/19 = p + 3 (p = quotient)
x = 19p + 3 ..........(2)
Equate (1) and (2)
x = 11y + 3 = 19p + 3
11y + 3 = 19p + 3
11y = 19p + 3 -3
11y = 19p
Divide both sides by 11
11y/11 = 19p/11
y = 19p/11
y and p are integers. 19 is a prime number. P/11 is also an integer
y = 19(integer)
This implies that y is a multiple of 19. When divided by 19, there is no remainder. The remainder is 0
Answer:
(
4
x
−
1
)
(
x
−
3
)
Step-by-step explanation:
Factor by grouping.
The smallest y can be is y = -1. The largest it can be is y = 1. The value of y can be anything in between. The value of y is a real number.
Answer: Choice D) All real numbers between -1 and 1 including -1 and 1Note: we can write that as
![-1 \le y \le 1](https://tex.z-dn.net/?f=-1%20%5Cle%20y%20%5Cle%201%20)
which in interval notation would look like
![[-1, 1]](https://tex.z-dn.net/?f=%5B-1%2C%201%5D%20)
. The square brackets tell us to include the endpoints.