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Kobotan [32]
3 years ago
13

Five children are the following ages: 12,13,11,11 and 13. What is their mean age?

Mathematics
2 answers:
Liula [17]3 years ago
8 0
Add all the ages up
60 divide by 5 = 12
the mean is 12
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

12

Step-by-step explanation:

add all the ages then divide by total number of different ages:12,13,11,11 and 13=60, 60/5=12

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James gave Robert half a candy bar. Robert gave his sister half of what he had. What fraction of the whole candy bar did Robert
Evgesh-ka [11]

Answer:

1/4

25%

Step-by-step explanation:

Robert has 1/2 of the candy bar

If he gave his sister half, she has 1/2 x 1/2 = 1/4 of the candy bar

To convert 1/4 to percentage, multiply by 100

1/4 x 100 = 25%

7 0
3 years ago
PLEASE HELP ME!!!!!!!!
GREYUIT [131]

Answer:

  The solution to the system of equations (x, y) = (2, 4) represents the month in which exports and imports were equal. Both were 4 in February.

Step-by-step explanation:

We're not sure what "system of equations" is being referenced here, since no equations are shown or described.

__

Perhaps your "system of equations" is ...

  f(x) = some equation

  g(x) = some other equation

Then the solution to this system of equation is the pair of values (x, y) that gives ...

  y = f(x) = g(x)

If x represents the month number, then the solution can be read from the table:

  (x, y) = (2, 4)

This is the month in which exports and imports were equal. Both numbers were 4 in February.

7 0
4 years ago
A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0
3 years ago
there is a traffic light at the intersection of Pine Street and Spruce Avenue. The traffic light on Pine Street follows a cycle.
Alex17521 [72]
The propability is the least chance because it is the lowest time frame that it is on for


8 0
3 years ago
D+7/−3=4<br> What is d?<br> Thanks!
givi [52]

Answer

\boxed {d= \frac{19}{3}}


Solution

Simplify both sides of the equation.


\frac{7}{3} + \frac{-7}{3}


We are left with d = 4+\frac{7}{3}


Add

\frac{12}{3}+\frac{7}{3} =\frac{19}{3}


Hence, d = \frac{19}{3}


7 0
3 years ago
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