The result of the evaluation of the expression is of 7.
<h3>How to evaluate the given expression?</h3>
We have to solve the expression. There are no precedence of operations involved, as the addition is inside the parenthesis, hence the solve the addition, solve the fraction, then subtract the results.
The solution to the addition of the numbers 14 and 17 is given by:
(14 + 17) = 31.
The solution to the fraction involving 6 multiplied by 12 and divided by 3 is given by:
6 x 12/3 = 72/3 = 24.
Then, considering the previous results, the result of the expression is given by:
(14 + 17) - 6 x 12/3 = 31 - 24 = 7.
More can be learned about evaluating an expression at brainly.com/question/4344214
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Answer:
<u>The company should promote a lifetime of </u><u>3589 hours</u><u> for these bulbs, so that only 2% of them burnout before the claimed lifetime.</u>
Step-by-step explanation:
Consider the lifetime of light bulbs is normally distributed. Then, μ = 4000 hours and σ = 200 hours.
Let X be the lifetime of bulbs. We need to find the lifetime before which only 2% (0.02) of the bulbs burn out. Suppose the value of this lifetime is y. then, we need to find out P(X<y) = 0.02.
We will use the z-score formula:
<u>z = (x-μ)/σ</u>
P(X<y) = 0.02
P((X-μ)/σ < (y-μ)/σ) = 0.02
P(z < (y-4000)/200) = 0.02
We can find the value of z at which the probability is 0.02 from the normal distribution (areas under the normal curve) table.
From the table we can see that 0.02 lies between z values -2.05 and -2.06. So,
z = [-2.05 + (-2.06)]/2
= -4.11/2
z = -2.055
So,
(y-4000)/200 = -2.055
y-4000 = -411
y = 4000 - 411
y = 3589 hours
<u></u>
<u>The company should promote a lifetime of </u><u>3589 hours</u><u> for these bulbs, so that only 2% of them burnout before the claimed lifetime.</u>
Answer: -8<y<12
Step-by-step explanation:
Answer:
He will earn $140, my bad miss calculated...
Step-by-step explanation:
Its 140....
i think i is 56 do you have answer choices?