All categories

2 years ago

Can any help me 10 points!!!!!! Its to pass math

Mathematics

2 answers:

guajiro [1.7K]2 years ago

4 0

Answer:

Option 4

Step-by-step explanation:

3x(x+2)-4(x+2)

(3x-4)(x+2)

3x²+6x-4x-8

3x²+2x-8

Brainliest please

BigorU [14]2 years ago

3 0

Answer:

(x + 2)(3x - 4)

3x^2 + 2x - 8

Step-by-step explanation:

Factor out x + 2.

You get: (x + 2)(3x - 4)

Now multiply it out:

(x + 2)(3x - 4) = 3x^2 - 4x + 6x - 8 = 3x^2 + 2x - 8

You might be interested in

cathi scored 6 baskets in each of her last 3 basketball games. Each basket was worth 2 points. how many points did cathi score i

jonny [76]

Answer:

p=36

Step-by-step explanation:

3(6*2)=p

3(12)=p

36=p

Sorry if its hard to understand I'm new to anwering questions on brainly

4 0

3 years ago

What's 6/7 written as a fraction with a denominator of 42

zimovet [89]

36/42
multiply the top and bottom by 6.
7 x 6 = 42
6 x 6= 36

3 0

2 years ago

The temperature started at 82° and continued to rise at a rate of 0.6° each hour the temperature is now 85° determine the number

Gnesinka [82]

Answer:

5 hours

Step-by-step explanation:

Our goal here is 3 F because 82+3=85

Ok so you start at 82. For example, you can do 0.6×1=0.6 (no)

0.6×2=1.2 (no)

0.6×3=1.8 (no)

0.6×4=2.4 (no)

0.6×5=3 (yes)

82°+3°=85°

8 0

3 years ago

Which expression is a factor of 4ab + 4a − 3b − 3?

e-lub [12.9K]

<span>4ab + 4a − 3b − 3
=4a(b + 1) - 3(b+1)
= (b+1)(4a - 3)

(b+1) and (4a - 3) are factors

answer
</span><span>4a − 3</span>

7 0

2 years ago

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0

3 years ago