Answer:
d ) f(x)= -5x-19 is most likely
The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
C. 8
Step-by-step explanation:
I almost thought this was going to be Pythagorean Theorem, but no.
Use Cosine Law:
cos θ = 
θ = cos−1(0.6)
θ = 53.130...
Now use the SOHCAHTOA ratio for sine (
) to find x now that you have one angle:
sin θ = 
x = 10sinθ (θ isn't needed to be written out as it is shown in the equation above)
x = 8
The exact number is 8,784 toffees but if you want me to estimate to the nearest tens then it would be 8,780
Answer:
g^2 + 4
I literally do not know how to explain it. I solved this problem with the clues like sum and squared. I looked at where these words were located.
