The answer for the picture would be 21
1.19 - 19%
0.00067=67X10^5 so
67X10^5-2.3X10^5
64.7X10^5 which can be expressed as:
6.47X10^6
(not sure if it matters to you or not, but technically we only had two significant figures so it should be rounded to 6.5X10^6)
1.
a.) 2q + 5r
2(7) + 5(-2)
14 - 10 = 4
b.) 3(p + 6) + q + r Plug in the numbers
3(5 + 6) + 7 - 2 Solve inside the parentheses first
3(11) + 7 - 2
33 + 5 = 38
2.
a.) m(3m + 4n)
2(3(2) + 4(3))
2(6 + 12)
2(18) = 36
b.) n²(m + p²)
(3)²(2 + (-5)²)
9(2 + 25)
9(27) = 243
c.) 3m(8 + n) + n²
3(2) (8 + 3) + 3²
6(11) + 9
66 + 9 = 75
plz plz mark brainliest if it helps
Answer:
D. No, there isn’t enough information because only two pairs of corresponding sides can't be used to prove that two triangles are congruent.