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aev [14]
3 years ago
7

If (x+y)^2=125xy,show that, 2 log (x+y) = 3 log 5+log x+ log y​

Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0

Formulas used :

loga^ x = x  \ log a

logab = log a + logb

Steps :

(x+y)^2 = 125xy\\\\log(x+y)^2 = log(125xy)\\\\2log(x+y) = log 125 + log x + log y\\\\2log(x+y) = log 5^3+ log x + log y\\\\2log(x+y) = 3 log 5 + log x + log y\\\\

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write the equation of a line in slope intercept form that is parallel to the line x+5y=10 and goes through the point (-5,6)
lilavasa [31]

Answer:

The equation would be y = -1/5x + 5

Step-by-step explanation:

To find the equation of this new line, we first need to identify the slope of the first line. We do this by putting it into slope intercept form.

x + 5y = 10

5y = -x + 10

y = -1/5x + 2

In slope-intercept form, the slope is always the coefficient of x. This makes the slope of the first equation -1/5. Since parallel lines have the same slope, our new slope will also be -1/5.

Given that and the point, we can solve for the equation using point-slope form.

y - y1 = m(x - x1)

y - 6 = -1/5(x + 5)

y - 6 = -1/5x - 1

y = -1/5x + 5


4 0
3 years ago
Did I do this correctly??please help​
soldier1979 [14.2K]
I’m not sure, hope this helped
5 0
2 years ago
Read 2 more answers
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VMariaS [17]

Answer:

x=3.5

Step-by-step explanation:

subract 5 on the other side, than divide by 2

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You move left 4 units and right 3 units. You end at (-2, -1). Where did you start?
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Step-by-step explanation:

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