Answer:
The midpoint of A and B is (0, 4).
Step-by-step explanation:
Use the midpoint formula, ((x₁ + x₂)/2 , (y₁ + y₂)/2)
First, solve for the x part.
(2 + (-2))/2
0/2
0
So the x-coordinate of the midpoint is 0.
Then, solve for the y part.
(3 + 5)/2
8/2
4
So the y-coordinate of the midpoint is 4.
The answer is the first one.
Explanation:
X^3 stays the same because there are no other cubed numbers in the problem
Next you combine the x^2s
The x^2s are +3x^2 and +2x^2
Since they are both positive, you add them: 3x^2 + 2x^2 = 5x^2
Next you do the x values
-x and +6x, also known as 6x - x = 5x
Lastly, you just add in the -2 and get:
X^3 + 5x^2 + 5x - 2
Answer:
There are 719,115.8179 KG of fuel stored in the external tank
Step-by-step explanation:
102619.377 + 616496.4409 = 719,115.8179
Answer: The correct option is D, i.e., 15 units.
Explanation:
It is given that the length of segment TR can be represented by 5x-4.
From figure it is noticed that the side TR and RV is equal and the length of segment RV is 2x+5. So,
![5x-4=2x+5](https://tex.z-dn.net/?f=5x-4%3D2x%2B5)
![3x=9](https://tex.z-dn.net/?f=3x%3D9)
![x=3](https://tex.z-dn.net/?f=x%3D3)
The value of x is 3, so the length of side RV is,
![2x+5=2(3)+5=11](https://tex.z-dn.net/?f=2x%2B5%3D2%283%29%2B5%3D11)
In triangle TRS and angle VRS,
TR=VR
![\angle TRS=\angle VRS=90^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20TRS%3D%5Cangle%20VRS%3D90%5E%7B%5Ccirc%7D)
RS=RS (common side)
By SAS rule of congruence triangle,
![\triangle TRS\cong\triangle VRS](https://tex.z-dn.net/?f=%5Ctriangle%20TRS%5Ccong%5Ctriangle%20VRS)
Therefore the side TS and VS are congruent sides.
From figure it is noticed that the length of side TS is 6x-3, therefore the length of side VS is also 6x-3.
![VS=6x-3=6(3)-3=15](https://tex.z-dn.net/?f=VS%3D6x-3%3D6%283%29-3%3D15)
Hence, the length of side VS is 15 units and option D is correct.