We have been given a quadratic function 
and we need to restrict the domain such that it becomes a one to one function.
We know that vertex of this quadratic function occurs at (5,2).
Further, we know that range of this function is 
.
If we restrict the domain of this function to either ![(-\infty,5]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C5%5D)
or 
, it will become one to one function.
Let us know find its inverse.
Upon interchanging x and y, we get:
Let us now solve this function for y.
Hence, the inverse function would be 
if we restrict the domain of original function to and the inverse function would be 
if we restrict the domain to .
Answer:
-2 , -10 & -99
Step-by-step explanation:
1)
⇒ x + 6 = 4
⇒ x = 4-6
⇒ x = (-2)
2)
⇒x - (-4) = -6
⇒ x + 4 = -6
⇒ x = -6-4
⇒ x = -10
3)
⇒2(x-1) = -200
⇒ x - 1 = -200/2
⇒ x - 1 = -100
⇒ x = 1 - 100
⇒ x = (-99)
Answer:50.27
Step-by-step explanation:
<h3>
Answer:</h3>
see attached for a graph
domain and range: all real numbers
<h3>
Step-by-step explanation:</h3>
The function is written in slope-intercept form, showing that it has a slope of -3 and a y-intercept of +7. The y-intercept (0, 7) is a point on the line, as is a point 1 unit to the right and down 3 units, (1, 4).
The graph will be the line through these two points.
_____
As with any odd-degree polynomial function, both domain and range are all real numbers: (-∞, ∞).
Answer:
The first one
Step-by-step explanation:
