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mestny [16]
4 years ago
13

Money Flow The proceeds from the sale of a building will yield a uniform continuous flow of $10,000 a year for 10 years. Find th

e final amount at an interest rate of 10.5% compounded continuously.
Mathematics
1 answer:
alexdok [17]4 years ago
3 0

Answer:

10500

Step-by-step explanation:

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The LCD for the fraction 1/3, 3/4, 5/32, and 8/9 is
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D 288 1/3 = 96/288     3/4 = 216/288     5/32 = 45/288      8/9 = 256/288 

1/3 times 96    3/4 times 72     5/32 times 9     8/9 times 32 

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Find y.<br><br> y - 4 = 3x - 5y
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y = -1 + -0.75x
explanation:
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You would divide 4.6 from both sides of the inequality symbol to get x standing alone.
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3 years ago
A restaurant operator in Accra has found out that during the partial lockdown, if she sells a plate of her food for GH¢20 each,
Lilit [14]

Answer:

Step-by-step explanation:

First, note this parameters from the question.

We let x = number of $5 increases and number of 10 decreases in plates sold.

Our Revenue equation is:

R(x) = (300-10x)(10+5x)

We expand the above equation into a quadratic equation by multiplying each bracket:

R(x) = 3000 + 1500x - 3000x - 1500x^2

R(x) = -1500x^2 - 1500x + 3000 (collect like terms)

Next we simplify, by dividing through by -1500

= 1500x^2/1500 - 1500x/1500 + 3000/1500

= X^2 - x + 2

X^2 - x + 2 = 0

Next, we find the axis of symmetry using the formula x = -b/(2*a) where b = 1, a = 1

X = - (-1)/2*1

X = 1/2

Number of $5 increases = $5x1/2 = $2.5

=$2.5 + $20 = $22.5 ticket price gives max revenue.

7 0
3 years ago
The present age of father is thrice as old as the age of daughter 5 years ago. If 5 years hence ,the age of father will be twice
pav-90 [236]

Answer:

<em>Hence the daughter's present age is 15 years</em>

<em>The fathers present age is 35 years</em>

<em></em>

Step-by-step explanation:

Let the present age of daughter be x

Let the present age of father be y

5 years ago;

Daughter's age = x - 5

Fathers age = y - 5

If the present age of father is thrice as old as the age of daughter 5 years ago, then;

y - 5 = 3(x-5)

y - 5 = 3x-15

y = 3x - 10 .... 1

In 5 years time;

Daughters age = x + 5

Fathers age = y + 5

If the age of father will be twice the age of his daughter in 5 years time then;

y+5 = 2(x+5)

y+5 = 2x + 10

y = 2x + 5 .....2

Equate 1 and 2;

3x - 10 = 2x + 5

3x - 2x = 5 + 10

x = 15

Since y = 2x + 5

y = 2(15) + 5

y = 35

<em>Hence the daughter's present age is 15 years</em>

<em>The fathers present age is 35 years</em>

<em></em>

3 0
3 years ago
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