3 years ago

If y = 4x, what is the value of 3y + 2(3y + 5) - x in terms of x?

Mathematics

1 answer:

USPshnik [31]3 years ago

7 0

Answer:

13/3

Step-by-step explanation:

3(4x)+6(4x)+30-x

39=9x

divide 9 on each side

x=13/3

yw if its right make me brainliest

You might be interested in

(-4,2) (2-3) midpoint

Sedbober [7]

Answer:

(-1, -1/2)

Step-by-step explanation:

use the midpoint formula(x1+x2/2, y1+y2/2)

-4+2/2, 2+-3/2

-4+2=-2/2=-1

2+-3=-1/2

(-1, -1/2)

3 0

3 years ago

How do you simplify a fraction with a denominator of a variable like this <br> 6x/x

Georgia [21]

Step-by-step explanation:

The x's will simply cancel each other out and you will be left with a 6

hope it makes sense

6 0

2 years ago

I need explanation and answer please,thanks.

Alla [95]

What’s the question?

3 0

3 years ago

Use the Distributive Property to simplify the expression<br> 4(c - 2)

xeze [42]

Answer

Step-by-step explanation:

4xc=4c

4x-2= -8

4c-8

3 0

3 years ago

Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4

Alik [6]

Answer:

$\alpha=3$

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

$(x-h)^2+(y-k)^2=r^2$

We are given the equation of a circle as

$3x^2+3y^2-6\alpha x+12y-3\alpha=0$

Note we have corrected it by adding the square to the y. Simplify by 3

$x^2+y^2-2\alpha x+4y-\alpha=0$

Complete squares and rearrange:

$x^2-2\alpha x+y^2+4y=\alpha$

$x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4$

$(x-\alpha)^2+(y+2)^2=r^2$

We can see that, if r=4, then

$\alpha+\alpha^2+4=16$

Or, equivalently

$\alpha^2+\alpha-12=0$

There are two solutions for $\alpha$ :

$\alpha=-4,\ \alpha=3$

Keeping the positive solution, as required:

$\boxed{\alpha=3}$

8 0

3 years ago