Answer:B
Step-by-step explanation:
A. y = 2x-11
B. y = 2x-10
c. y = 2x-4
D. y=2x-2
Recall, the slope intercept equation
y= mx+c
Assuming c is held constant in each scenario
Looking at A
m = 2, c = -11
Equation of the line that passes through the point (3.-4)
-4 = 2×3 + c
c =-10
-10 does not correspond to -11 given
Let's try B
m= 2, c = -10
Equation of the line that passes through the point (3.-4)
-4 = 2×3 + c
c = -4-6 = -10
This intercept correspond with the intercept in B which is -10
Let's look at C
m= 2, c = -4
Equation of the line that passes through the point (3.-4)
-4 = 2×3 + c
c = -4-6 = -10
-10 does not correspond to -4 given
Let's try D
m= 2, c = -2
Equation of the line that passes through the point (3.-4)
-4 = 2×3 + c
c = -4-6 = -10
-10 does not correspond to -2 given
SOLUTION
From the question, we want to find the probability of selecting a slip of paper with the letter t on it, then selecting the letter r, with replacement.
This means the probability of selecting t and r.
That is
There are 12 letters (total outcomes). And there are 2r and 2t.
So probability becomes
Hence the answer is
Answer:
When sampling from a population, the sample mean will: be closer to the population mean as the sample size increases.
Step-by-step explanation:
The sample mean is not always equal to the population mean but if we increase the number of samples then the mean of the sample would become more and more closer to the population mean.
Usually the population size is very huge that is why we select a random sample from the population, care must be taken to ensure randomized sampling otherwise results would not be accurate. After that we have to make sure that the number of samples are enough for the given population size. The number of samples depends upon the shape of the population. If the population is normal than according to central limit theorem, a less number of samples would be enough to ensure normal distribution of sampling mean, otherwise a greater sample size will be required.
We know that
<span>The nine radii of a regular Nonagon divides into 9 congruent isosceles triangles
</span>therefore
[the area of <span>a regular nonagon]=9*[area of isosceles triangle]
</span>[area of isosceles triangle]=b*h/2------> 15*20.6/2----> 154.5 cm²
so
[the area of a regular nonagon]=9*[154.5]------> 1390.5 cm²
the answer is
1390.5 cm²
