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3 years ago

In which zone is Venezuela? Torrid Temperate Capricorn Cancer

Geography

2 answers:

Sati [7]3 years ago

6 0

The answer is cancer

damaskus [11]3 years ago

5 0

Answer:

The Torrid Zone, between the Tropic of Cancer at 23° 27' N and the Tropic of Capricorn at 23° 27' S, covers 39.78% of Earth's surface. The South Temperate Zone, between the Tropic of Capricorn at 23° 27' S and the Antarctic Circle at 66° 33' S, covers 25.99% of Earth's surface.

Explanation:

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3 years ago

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How much does the air weigh within a column that is 1 square inch in area that extends from sea level all the way to the top of

iren2701 [21]

Answer:

option (c) 14.7 lbs

Explanation:

Data provided in the question:

Area of the column = 1 square inch

Now,

we know Air pressure at the ground surface level from the atmosphere

= 14.7 Psi

also, it can be represented as

14.7 Psi = 14.7 pounds per square inch

Therefore,

Weight of the air weigh within a column that is 1 square inch in area

= Air pressure × Area

= 14.7 pounds per square inch × 1 square inch

= 14.7 pounds i.e 14.7 lbs

Hence,

The answer is option (c) 14.7 lbs

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3 years ago

1. What are central asia’s three main physical features?

Nimfa-mama [501]

Answer:Central Asia's main physical features are highlands, deserts, and steppes

Explanation:

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3 years ago

Find the area of the following shape

irina1246 [14]

Answer:

The area will be

Explanation:

There are 42 full squares, and with the rest shards remaining, we add up to 56 squares.

4 0

3 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints

zzz [600]

Answer:

y= -7/2x-26/2 or y= -7/2x-13

Explanation:

To solve this question you need all of these formulas:

gradient: $\frac{y2-y1}{x2-x1}$ , Point-Slope $y-y1=m(x-x1)$ ,

perpendicular m $(m1)x(m2)=-1$ , Midpoint $(\frac{x1+x2}{2}$ , $\frac{y1+y2}{2} )$

and equation of a line $y=mx+c$

where m stands for gradient

First things first.

To start you have to know the data of the line that includes the two endpoints, so you calculate its gradient (m) of this line with the gradient fromula: $m=\frac{-4-(-8)}{5-(-9)}$ , which equals 4/14 or 2/7

(It can also be called rise/run) (Remember the rule of signs where - and - equal +)

with that information you can proceed with the point-slope or point-gradient formula, so you plug the values: y-(-8) = 2/7 (x-(-9)), which results in y+8=2/7(x+9) and then y+8=2/7x+18/7.

To finish the equation you move eight to the other side. To simplify things you can change it into a fraction as I did, and remember to change signs.

y=2/7x+18/7 -8 -> y=2/7x+18/7-56/7 . This gives us the number of y=2/7x-38/7, which is the equation of the first line.

Now to know the gradient of the second line you apply the formula of perpendicular bisector where m1 x m2 = -1. We know m1 (gradient of the first line) is 2/7, so m2 = $\frac{-1}{2/7}$ = -7/2. m2 is therefore -7/2

Now you have to know the midpoint between the two endpoints, which will act as the start point of the perpendicular bisector

M (midpoint) = $(\frac{-9+5}{2} ,$ $\frac{8+(-4)}{2} )$ , which give us the coordinates of (-2, -6)

(remember, x coordinate is always first)

with this point we can apply again the point-slope formula to know the equation of the line:

y-(-6)=-7/2(x-(-2)) -> y+6=-7/2(x+2) -> y+6=-7/2x - 14/2

Move the 6 to isolate the y

y=-7/2x -14/2 - 12/2

which equals y= -7/2x -26/2

You can check the results in this page: GraphPlotter

https://www.transum.org/Maths/Activity/Graph/Desmos.asp

To make sure the answer is correct.

Hope it helps :)

8 0

3 years ago