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2 years ago

8

(picture)complete it

1 answer:

pogonyaev2 years ago

4 0

His estimated answer would be 120 and for number 4 it would be a) 300 b) 700 and c) 1500 hope this helped. Mark as brainliest?

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In her wallet, Ms. Thompson has one-dollar, five-dollar and ten-dollar bills totaling $171. She has the same number of five-doll

Phantasy [73]

6 one-dollars = $6 15 five-dollars = $75 9 ten-dollars = $90 Add them all up to get $171, so that is correct. Add the number of one-dollar bills and the number of ten-dollar bills together. 6 + 9 = 15, which is the number of five-dollar bills, so that is correct as well. Add all the numbers of bills together, 6 + 9 + 15 = 15 + 15 = 30.

4 0

3 years ago

Find the mean and the median of this data set: 8, 6, 6, 3, 72, 7, 4, 2

icang [17]

Answer:

median: 6 ; mean: 13.5

Step-by-step explanation:

The median is where you line up the numbers from least to greatest and add the 2 that are left since it was an even number and you get 6. The mean is where you add all 8 numbers and divide by 8, since that is how many numbers there are.

5 0

3 years ago

1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a

katovenus [111]

1. Let a and b be coefficients such that

$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

Combining the fractions on the right gives

$\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}$

$\implies 1 = (2a+b)x + 3a$

$\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23$

so that

$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C$

Given that y = 1 when x = 1, we find

$\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)$

so the particular solution to the ODE is

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

We can solve this explicitly for y :

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

2. b. When x = 9, we get

$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

8 0

2 years ago

For the function f(x) = –2(x + 3)2 − 1, identify the vertex, domain, and range.

gregori [183]

F(x) = -2(x + 3)^2 - 1
vertex = (-3, -1)
domain is all real number values of x and
range is all real numbers values of y less than or equal to -1.

5 0

3 years ago

Read 2 more answers

Drey makes $10 an hour plus $15 an hour for every hour of overtime. Overtime hours are any hours more than 40 hours for the week

gregori [183]

Part A: W = 10x

Part B: S = 400 + 15y

Part C: 490 = 400 +15y
-400 -400
90 = 15y
6 = y, so he worked a total of 46 hours.

6 0

3 years ago