Answer:
The graph in the attached figure
Step-by-step explanation:
we have
The solution of the inequality is the shaded area below the dashed line
The equation of the line is 
The slope of the line is positive 
The y-intercept of the line is the point 
The x-intercept of the line is the point 
so
The graph in the attached figure
Answer:
The expected number of floors the elevator stops at, not counting the ground floor is =
n*(1-(1-1/n)^m)
Step-by-step explanation:
Here, we want to know the expected number of floors the elevator stops at.
let X1,X2,X3,..Xn are indicator variable for which value =1 if at least one person stops on that floor otherwise value is 0
P(at least one person stops at floor Xj)=1-P(none of m people stops at floor j)
=1-(1-1/n)^m
here total number of floors on elevetor Stops X=X1+X2+X3+...+Xn
hence expected number of floors on elevetor Stops
E(X)=E(X1)+E(X2)+E(X3)...+E(Xn)
=(1-(1-1/n)^m )+(1-(1-1/n)^m )+(1-(1-1/n)^m )+(1-(1-1/n)^m )+..... n times
=n*(1-(1-1/n)^m)
Answer:
79
Step-by-step explanation:
The SUM of ... 9. The sum of r and 45 is 79. 10. The quotient of x and 7 is equal to 13. r + 45 = 79.
First of all we will find per ounce price of each trail mix.
Let us find per ounce price of cran-soy trail mix.
Now we will find per ounce cost of raisin-nuts mix.
Let us find per ounce price of lots of cashews mix.
Now we will find per ounce cost of nuts for you mix.
Now let us order our trail mix brands from least expensive to most expensive by their per ounce price.
Nuts for you (0.4), Raisin-nuts mix (0.487), Cran-soy trail mix (0.598), Lots of cashews mix (0.88).
Answer:
see below
Step-by-step explanation:
Part A
the probability that a randomly chosen flight arrives on time = number of flights that arrive on time/ total number of flights
Part B
The same as part A but applied for each carrier and then comparing who has the closest number to 1
Part C
total number of flights that arrives on time in PHL/ total number of flights that are on time for all airports
Part D
look for the carrier Hawaiian Airlines (HA) first and then number of flights that arrives on time for HA/ total number of flights HA has
Part E
look for OO and WN in table
add up all flights made ( all airports) for OO and WN
add up all flights on time for OO and WN
divide flights on time by all flights made
Hope this will help you. :)
