Answer:
Length:8 m
Width:3 m
Step-by-step explanation:
<u><em>The complete question is</em></u>
If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
step 1
<em>Perimeter of rectangle</em>
we know that
The perimeter of rectangle is equal to

we have

so

Simplify
 -----> equation A
 -----> equation A
step 2
Perimeter of triangle
The perimeter of triangle is equal to


so

Multiply by 2 both sides

 ----> equation B
 ----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (8,3)
see the attached figure
therefore
The dimensions of the rectangle are
Length:8 m
Width:3 m
 
        
             
        
        
        
Answer:
yes the graph reflects over the y-axis because if you see in the y axis the line show that it is the pont to the axis 
hope it helps
 
        
             
        
        
        
Answer:
Step-by-step explanation:
It would be 2.43ft cubed. You first have to multiply 6 x 9 to get 54 and then Do 54 x 4.5 to get 243 ft cubed. Next you have to put it in fraction form 243/100. After that you have to divide 243 by hundred( you can do this by moving the decimal place two places to the left) and you get the answer 2.43 ft cubed
 
        
             
        
        
        
4ab^5c (3a^4b^2c^3) = 12a^5b^7c^4...answer B