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Anit [1.1K]
3 years ago
6

A 2-column table with 4 rows. Column 1 is labeled Situation with entries increasing, difference, finding part of a total, sharin

g or grouping. Column 2 is labeled Operation with entries +, minus, times, divided by. Jackson downloaded 6 songs for $7.80. What was the cost of each song? The variable, c, represents The cost of each song is part of a total, so the operation is The correct equation to solve this problem is
Mathematics
2 answers:
podryga [215]3 years ago
7 0

Answer:

Review the proof. A 2-column table with 8 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine squared (StartFraction x Over 2 EndFraction) = StartFraction sine (x) + tangent (x) Over 2 tangent (x) EndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction sine (X) + StartFraction sine (x) Over cosine (x) EndFraction OverOver 2 (StartFraction sine (x) Over cosine (x) EndFraction) EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction question mark Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction (sine (x)) (cosine (x) + 1) Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = (StartFraction (sine (x) ) (cosine (x) + 1 Over cosine (x) EndFraction) (StartFraction cosine (x) Over 2 sine (x) EndFraction), cosine squared (StartFraction x Over 2 EndFraction) = StartFraction cosine (x) + 1 Over 2 EndFraction, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction cosine (x) + 1 Over 2 EndFraction EndRoot, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 + cosine (x) Over 2 EndFraction EndRoot.

Step-by-step explanation:

Review the proof. A 2-column table with 8 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine squared (StartFraction x Over 2 EndFraction) = StartFraction sine (x) + tangent (x) Over 2 tangent (x) EndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction sine (X) + StartFraction sine (x) Over cosine (x) EndFraction OverOver 2 (StartFraction sine (x) Over cosine (x) EndFraction) EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction question mark Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction (sine (x)) (cosine (x) + 1) Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = (StartFraction (sine (x) ) (cosine (x) + 1 Over cosine (x) EndFraction) (StartFraction cosine (x) Over 2 sine (x) EndFraction), cosine squared (StartFraction x Over 2 EndFraction) = StartFraction cosine (x) + 1 Over 2 EndFraction, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction cosine (x) + 1 Over 2 EndFraction EndRoot, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 + cosine (x) Over 2 EndFraction EndRoot.

Mars2501 [29]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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Mr. Jones purchased two sodas.
kondaur [170]

Answer:

  the prices were $0.05 and $1.05

Step-by-step explanation:

Let 'a' and 'b' represent the costs of the two sodas. The given relations are ...

  a + b = 1.10 . . . . the total cost of the sodas was $1.10

  a - b = 1.00 . . . . one soda costs $1.00 more than the other one

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Adding these two equations, we get ...

  2a = 2.10

  a = 1.05 . . . . . divide by 2

  1.05 -b = 1.00 . . . . . substitute for a in the second equation

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The prices of the two sodas were $0.05 and $1.05.

_____

<em>Additional comment</em>

This is a "sum and difference" problem, in which you are given the sum and the difference of two values. As we have seen here, <em>the larger value is half the sum of the sum and difference</em>: a = (1+1.10)/2 = 1.05. If we were to subtract one equation from the other, we would find <em>the smaller value is half the difference of the sum and difference</em>: b = (1.05 -1.00)/2 = 0.05.

This result is the general solution to sum and difference problems.

5 0
3 years ago
Which is greater 3/8 or 2/3
Olenka [21]
2/3 is greater because 3/8 is less than 1/2 while 2/3 is greater than 1/2
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3 years ago
What is the product of 2.678 and 9.7? A) .259766 B) 25.9766 C) 2.59766 D) 259.766
solmaris [256]
When you multiply it out by hand to get 
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you place the decimal point in the answer by counting the number of decimal places of the multiplicands.
   2.678 has 3 decimal places
   9.7 has 1 decimal place
The product of these numbers will have 3+1 = 4 decimal places, so will look like
   B) 25.9766


___
You can also get there by considering that the product is about 10×2.6, so is about 26. That will tell you the decimal point goes after the first two left-most digits.
6 0
4 years ago
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Can someone help me with this problem? ​
Ray Of Light [21]

Answer and Step-by-step explanation:

Answer is in picture.

We use the cosine trig function (adjacent side over hypotenuse = cos of an angle) to find m.

The angles are split perfectly in half, half of 90, which is 45, so the other angles are 45.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

4 0
3 years ago
one week you spent $24 on 6 subway tickets and 4 express bus tickets. the next week you spent $27 on 3 subway tickets and 7 expr
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I think its $30 because 6 and 4 tickets is 24.then it turned out 27.i think there is a pattern i added 3 beause 4 plus 3 is 7 and i got 30
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