The answer is D, (1/3, 4).
Hope this helped!
<span>distance=6390km; time=9 hrs; rate=710kph
With the wind Data:
distance=5150km; time=5hrs; rate=1030kph
EQUATIONS:
airspeed+jetstream=1030
airspeed-jetstream=710
Subtract these equations to get:
2jetstream=320kph
jetstream=160mph </span>
Answer:
34 ft. tall
Step-by-step explanation:
Your first step should to draw a diagram. When you do that, your diagram should look like a right triangle, the leg, or the distance from the firetruck to the building, (we'll call this a) should be 30ft. and the hypotenuse, or the ladder (we'll call this c), should be 45ft.
Now we have a visual so it'll be easier.
We know that this problem is a right triangle and we know that to solve for a missing side of a right triangle you use pythagorean theorem: a^2+b^2=c^2
We know one leg 'a' and the hyp. 'c' and we just need to find 'b' the other leg (aka the building):
Plug in numbers and simplify:
30^2+b^2=45^2
900+b^2=2025
b^2=1125
≈33.54 OR 34 ft. tall
The given trapezoid will have the sides ST, TV, VU, and US. Each of these can be assigned as base or legs. By this, it can be deduced that the given sides, SV and TU are the diagonals. Because the trapezoid is isosceles, the values of SV and TU should also be equal.
SV = TU
3x - 11 = x + 13
Transpose the terms with x and the constants in each sides of the equation.
3x - x = 13 + 11
2x = 24
<em> x = 12</em>
Thus, the value of x from the equation is 12.
