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2 years ago

Please help me I’m currently failing this class ills really appreciate it

Mathematics

1 answer:

Ganezh [65]2 years ago

3 0

Answer:

Question 1:

(3)

x 3 5 7 9

f(x) 2 4 2 4

Question 2:

(2) whole numbers

Step-by-step explanation:

In a function, each x-value must only have 1 y-value, but a y-value can have multiple x-values.

A whole number is any positive number that is not a fraction. You cannot have negative devices nor a fraction of a device.

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Solve 4a = 20

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Here's the solutions :

1. solve for a :

$4a = 20$

$a = \dfrac{20}{4}$

$a = 5$

2. solve for y :

$3y + 9 = 24$

$3y = 24 - 9$

$3y = 15$

$y = \dfrac{15}{3}$

$y = 5$

3. solve for y :

$\dfrac{y}{3} - 5 = 4$

$\dfrac{y}{3} = 5 + 4$

$\dfrac{y}{3} = 9$

$y = 9 \times 3$

$y = 27$

4. solve for k :

$3 = 9 - 4k$

$3 - 9 = -4 k$

$- 6 = - 4 k$

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5. there's something wrong with this question.

6. solve for x :

$3x + 8 = 2$

$3x = 2 - 8$

$3x = - 6$

$x = \dfrac{ - 6}{3}$

$x = - 2$

i hope it helped...

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Two sides of a four sided figure have negative slopes which are the endpoints of the sides of this figure

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Rudiy27

Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.

If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.

If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.

However, the area x*y must be constant and = 100.

We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.

We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.

So, the difference between the max and min values of x+y = 101 - 20 = 81.

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For the first 80 miles of her road trip, Lina travels 10 miles/hour slower than she did for the remaining 50 miles of her trip.

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