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Jlenok [28]
3 years ago
11

PLEASE HELP IT'S URGENT THE ASSIGNMENT IS DUE TODAY Rewrite without absolute value for the given conditions:

Mathematics
1 answer:
Papessa [141]3 years ago
8 0

Answer:1. y=|x−3|+|x+2|−|x−5|, if -2<x< 3  = x

2. y=|x−5|+|x+5|, if x>5 = 2x

Step-by-step explanation:

i did that before

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khan academy is giving me only this explanation but won't go into detail and I cannot understand it for the life of me. how do I
Setler [38]

Answer:

12 - 4i

Step-by-step explanation:

-2i ( 2+6i)

Distribute

-2i * 2 + -2i *6i

-4i - 12 i^2

We know that i^2 = -1 so replace it

-4i - 12(-1)

-4i + 12

Then put in the order a+bi  where the real number comes first and the imaginary number comes last

12 - 4i

7 0
3 years ago
Whats 126545 x 14569865 x 45645158 x 56453258?
GrogVix [38]
The answer is 4.75099138998831 to the 27th. :)
6 0
3 years ago
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Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with μ=10
Tju [1.3M]

Answer: 0.8238

Step-by-step explanation:

Given : Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with \mu=106 and \sigma=15.

Let x denotes the scores on a certain intelligence test for children between ages 13 and 15 years.

Then, the proportion of children aged 13 to 15 years old have scores on this test above 92 will be :-

P(x>92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]

Hence, the proportion of children aged 13 to 15 years old have scores on this test above 92 = 0.8238

4 0
3 years ago
Find the next two terms in the sequence <br><br> 0.1,0.02,0.004,0.0008,0.00016
Nezavi [6.7K]

Answer:

0.00032 and 0.00064

8 0
3 years ago
3k - 2c + 8<br> use k = 7 and c = 4
Inga [223]

Answer:

21

Step-by-step explanation:

3 (7) - 2(4) + 8

21 - 8 + 8

13 + 8

21

6 0
3 years ago
Read 2 more answers
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