Part 1:
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:

Now,

Therefore, the radius of the circle is
10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

Now,

Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately
12.9 cm.
Answer:
0.87
Step-by-step explanation:
9514 1404 393
Answer:
£592 for 16 boxes
Step-by-step explanation:
The classroom floor area is ...
A = LW = (8.8 m)(2.2 m) = 19.36 m²
The cupboard floor area is ...
A = (2.3 m)(2.1 m) = 4.83 m²
Then the total area to be covered is ...
19.36 m² +4.83 m² = 24.19 m²
At 1.6 m² per box, the number of boxes required is ...
(24.19 m²)/(1.6 m²/box) = 15.12 boxes
If we assume we can only purchase whole boxes, we need to purchase 16 boxes to cover the floor. The cost will be ...
(16 boxes)(£37/box) = £592 . . . . cost of laminate to replace the floor
Answer:
W = 5 ft; L = 10 ft
Step-by-step explanation:
Start by representing the length and width:
W = W
L = 2W
Area of rectangle = L * W = 2W * W = 50 ft^2. Then 2W^2 = 50 ft^2.
Solving for the width W results in W^2 = 25 ft, or W = 5 ft.
The length, L, is therefore L = 2W = 10 ft.
Check: Does L * W = 50 ft^2? Does (5 ft)(10 ft) = 50 ft^2? YES