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ollegr [7]
3 years ago
12

Simplify the numerical expression 5.75 - 1/2 (20÷2.5) ÷ 2+6

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

5.75 - 1/2 times 8 divided by 2 + 6

Step-by-step explanation:

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Taybrownies1359Step-by-step explanation:

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48

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The school production of​ 'Our Town' was a big success. For opening​ night, 315 tickets were sold. Students paid ​$1.50 ​each, w
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8 0
4 years ago
Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar
horsena [70]

Answer:

P(A) = \frac{1}{9}

P(B) = \frac{1}{3}

P(C) = \frac{1}{729}

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

P(M) = \frac{1}{3}.

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is P(A) = \frac{1}{9}. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}.

C. If the probability that two people have been hired on a specific day of the week is 3(\frac{1}{3}) ^ 2, then the probability that 7 people have been hired on the same day is:

P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}

D. The probability is \frac{1}{729}. This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0
3 years ago
3 3/4 divided by 5/7
AysviL [449]

I think I already answered it to you from the same question you asked earlier.

But anyways, the answer is in the image below and the steps are also in one of the images too.

Hope this helps! :)

8 0
3 years ago
Read 2 more answers
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