In this question it basically wants you to leave Y alone in a side of the equation.
In this case,
For 3y=c
For Ay=w
For Y/c=w
Y=cw
For y/a=2c
y=2ac
For a=y+p
y=a-p
For C=y-k
y=C+k
1. find the area of the two triangles, including the shaded section. the formula for this is a=1/2bh
the height and base are both 24 inches. this is because you add the 10 from the side of the square to the 14 that is given
so:
a=1/2(24)(24)
a=(12)(24)
a=288 sq. inches
since there are two triangles, you would multiply the area by 2
a=2(288)
a=576 sq. inches
now, since you only need the unshaded section, you have to take away the shaded section, which is a square. to do this, you must calculate the area of the square and take it away from the area of both triangles.
a=576-(lw)
a=576- (10)(10)
a=576-100
a=476 sq. inches
that is your answer
3.888 :))))))))))))))))))))))))))
