All categories

2 years ago

48 is 32% of what number?

Mathematics

1 answer:

Irina18 [472]2 years ago

4 0

Answer:

150

Step-by-step explanation:

Because I looked it up

You might be interested in

5 less than 18 times the number x, is less than of equal to -45. write and inequality for this statement

swat32

Answer:

18x-5≤-45

Step-by-step explanation:

8 0

2 years ago

What is the volume of a square pyramid that is 8 feet tall with base edges of 3 feet?

Dennis_Churaev [7]

Answer : 8 ft
Explanation :
You can find the volume of a regular square pyramid using the formula volume = base area × height / 3. Hope it helps.

8 0

1 year ago

City A is due north of City B. Find the distance between City A (36 degrees 6 prime36°6′ north latitude) and City B (21 degre

vitfil [10]

Answer:

distance = 994.75 miles

Step-by-step explanation:

given data

City A = 36°6′ = 36° + $\frac{6}{60}$ = 36.1° = 36.1° × $\frac{\pi}{180}$ = 0.6297 rad

City B = 21°42′ = 21° + $\frac{42}{60}$ = 21.7° = 21.7° × $\frac{\pi}{180}$ = 0.3785 rad

multiply by π/180 to convert the degree to radian

radius of Earth = 3960 miles

to find out

distance between City A and City B

solution

we first get here central angle between A and B city is

central angle between A and B city = 0.6297 rad - 0.3785 rad

and

now by arc length so we get distance

distance = 3960 miles × (0.6297 rad - 0.3785 rad )

distance = 994.75 miles

5 0

2 years ago

A farmer has one square mile land . If he divides his land into square fields that are 1/4 mile long and 1/4 mile wide,how many

White raven [17]

A square field that is 1/4 mile long and 1/4 mile wide has area

$\dfrac{1}{4} \cdot \dfrac{1}{4} = \dfrac{1}{16}$

So, to know how many of these fields fit in the biggest field, you have to divide their areas:

$\dfrac{1}{\frac{1}{16}} = 16$

So, if the farmer divides his land into square fields that are 1/4 mile long and 1/4 mile wide, he will have 16 of these smaller fields.

8 0

2 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

8 0

2 years ago

Read 2 more answers