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Sergeeva-Olga [200]
3 years ago
6

The radius r of a sphere is 8.5mm. calculate the sphere's volume v

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0
Volume = 4/3 * PI * r^3
Volume = 4/3 * PI * 8.5^3
<span>Volume = 4.18879</span> * <span> <span> <span> 614.125 </span> </span> </span>
Volume = <span> <span> <span> 2,572.44 cubic centimeters

</span></span></span>



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A shorter style of cup is stacked tall. The graph displays the height of the stack in centimeters for different numbers of cups.
Strike441 [17]

Answer:

0.5

Step-by-step explanation:

We are looking for how much height is gained per cup added.

Height per cup added can be calculated by finding the slope of the line that runs through the two given points on the graph, (3, 5.5) and (8, 8).

Formula for slope =

Let,

3 0
3 years ago
Read 2 more answers
which is the rationalized form of the expression the square root of x divided by the square root of x +the square root of 7
Ilya [14]

Answer:

I assume your goal is to rationalize the denominator -

So you need to multiply the denominator by its conjugate.

So we have:

\frac{\sqrt{x} }{\sqrt{x}-\sqrt{7} } *\frac{\sqrt{x} +\sqrt{7} }{\sqrt{x} +\sqrt{7}}

->

\frac{x-\sqrt{7}\sqrt{x} }{x-7}

gg

8 0
3 years ago
You buy the following materials for the new extension. Calculate the cost of the bricks and cement and then work out the total c
bogdanovich [222]

<u>Answer:</u>

Cost of sand = £150

Cost of bricks =  £157.5

Cost of cement = £134

Total cost = £441.50

<u>Step-by-step explanation:</u>

We are given that:

2 tonnes of sand  is for £75.00 per tonne,

20 bags of cement  are for £6.70 per bag,

350 bricks at 45p each,

So, 2 tonnes of sand  at £75.00 per tonne = 2 * £75.00 = £150.00

20 bags of cement  at £6.70 per bag = 20 * £6.70 = £134.00

350 bricks at 45p each = 350 * £0.45 = £157.50

Therefore, the total cost of all the materials = £150 + £134 + £157.5 = £441.50

7 0
3 years ago
Solve the following system of equations. What is one x-value of a solution?
gulaghasi [49]

Answer:

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Step-by-step explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}

x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}

x = \frac{-36 \pm 33.11}{2}

x_1 = \frac{-36 + 33.11}{2}

x_1 = -1.445

x_2 = \frac{-36 - 33.11}{2}

x_2 = -34.555

5 0
3 years ago
Over the summer, for every 12 okra seeds Dana planted, 7 grew into plants. If he planted 120 okra seeds, how many grew into plan
Ipatiy [6.2K]
The answer is 70 because 

6 0
3 years ago
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