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otez555 [7]
2 years ago
10

What is the fraction 18/24 reduced to its lowest terms?

Mathematics
2 answers:
WINSTONCH [101]2 years ago
8 0
<em>First, find the greatest common factor (GCF) of the numerator and denominator.</em>

<u>Factors of 18</u>: 1, 2, 3, 6, 9, 18
<u>Factors of 24</u>: 1, 2, 3, 4, 6, 8, 12, 24
<u>Common Factors</u>: 1, 2, 3, 6
<u>GCF</u>: 6

<em>Now, divide the numerator by 6 and the denominator by 6.</em>

18 ÷ 6 = 3
24 ÷ 6 = 4

<em>Set these as your new numerator and denominator.</em>

\frac{3}{4}

The answer is (b).

anastassius [24]2 years ago
7 0
\boxed{ \frac{18^{\div6}}{24^{\div6}} ~\to~ \frac{3}{4} }
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3 years ago
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Softa [21]

Answer:

Step-by-step explanation:

f(x)  = 2x² + 14x - 4

= 2(x² + 7x) - 4

= 2(x² +7x + 3.5²) - 2(3.5²) - 4

= 2(x+3.5)² - 28.5

vertex (3.5, -28.5) = (7/2, -57/2)

The vertical intercept is the y-intercept, i.e., f(0) = -4.

The x-intercepts are the values of x for which y=0.

2x² + 14x - 4  = 0

x = [-14±√(14²-4(2)(-4))]/[2(2)] = [-7±√57]/2 ≅ -7.27, 0.27

5 0
2 years ago
Suppose that 80% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
Gwar [14]

Answer:

P=0.147

Step-by-step explanation:

As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2

We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.

We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) .  To find the required probability 3 mentioned probabilitie have to be summarized.

So P(9/16 )=  C16 9 * P(good brakes)^9*Q(bad brakes)^7

P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02

P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007

P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12

P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147

7 0
2 years ago
In a trivia game your team has -6 points. The other team has 15 points. What is the difference in points between the two teams
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4 0
3 years ago
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Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6
crimeas [40]

Answer:

  c.  3a^2b^11/2

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)/(a^c) = a^(b-c)

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3 0
2 years ago
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