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bagirrra123 [75]
3 years ago
11

How many times stronger is a magnitude 9.2 earthquake than a magnitude 6.4 earthquake? Round your answer to the nearest whole nu

mber.
Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

i have tried but have no idea

help me too haha

Step-by-step explanation:

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The length of a rectangular garden is 2 feet more than twice it's width. If the area is 40 square feet, how much fencing would b
Westkost [7]

Answer:

w =4 ft and l =10 ft

Step-by-step explanation:

Let w = width

l = 2w+2

A = l*w

A = (2w+2)(w)

 40  = (2w+2) w

Distribute

40 = 2w^2 +2w

Subtract 40

0 = 2w^2 +2w - 40

Dividing each side by 2

0 = w^2 +w -20

Factor

0 = (w+5) (w-4)

Using the zero product property

w+5 =0     w-4=0

w= -5  w=4

Since we cant have a negative length

w=4

l = 2w+2 = 2(4)+2 = 8+2 =10

7 0
3 years ago
The smaller triangle was dilated to form the larger triangle. What is the value of x?
Nikolay [14]
We know that
scale factor=measure larger triangle/measure smaller triangle---->18/12
scale factor=1.5
so
measure larger triangle=scale factor*measure smaller triangle

for the leg in the smaller triangle equal to 5
measure larger triangle=1.5*5-----> 7.5

the answer is
7.5
8 0
3 years ago
Read 2 more answers
Write a number with the digit<br> 8 in the tens place
maxonik [38]
A number in the tens place 84
4 0
3 years ago
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What number must you add to complete the square?<br> x^2 + 2x = -1
Andru [333]
\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}


If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248


\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}

6 0
3 years ago
Read 2 more answers
A square has a diagonal with the length of 8V7 inches. What is the length of the<br> sides?
Nikitich [7]

Answer:

approximately 13.9 inches

Step-by-step explanation:

That's 8√6, not 8V7.

The four sides are of the same length (x).  According to the Pythagorean Theorem, x² + x² = (diagonal length)² = (8√6)², or

2x² = 64(6) = 384

Dividing both sides by 2, we get:

x² = 192, or x² = 4(48).  Then the side length is x = √16√12, or

x = 4√4√3 = 8√3.  This is approximately 13.9 inches.

4 0
3 years ago
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