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bagirrra123 [75]

3 years ago

11

How many times stronger is a magnitude 9.2 earthquake than a magnitude 6.4 earthquake? Round your answer to the nearest whole nu

mber.

1 answer:

Hatshy [7]3 years ago

8 0

Answer:

i have tried but have no idea

help me too haha

Step-by-step explanation:

You might be interested in

Now find the sum what 2 5/6 and

salantis [7]

Answer:

$2 \frac{1}{5} + 1 \frac{5}{6} = 2 \frac{6}{30} + 1 \frac{25}{30} \\ \\ \frac{66}{30} + \frac{55}{30} = \frac{121}{30} \\ \\ \\ = 4 \frac{1}{30}$

I hope I helped you^_^

3 0

3 years ago

The claim is that the standard deviation of the speeds of drivers in Bradford is 8 mph. An experienced driver feels that this is

Irina-Kira [14]

Answer:

Null hypothesis is rejected. Standard deviation is > 8 miles per hour

Step-by-step explanation:

σ [Population standard deviation] = 8 , s [sample standard deviation] = s

n [no of items] = 8

H0 [Null] : σ = 8 ; H1 [Alternate - Right Tail] : σ > 8

χ2 = (n - 1) . s^2 / σ^2

= 49 x (10.5)^2 / 82 = 5402.25 / 64

χ2 = 84.410

df [degree of freedom] = n -1 = 50 - 1 = 49

P value (χ^2 49 > 84.410) = 0.00125

p = 0.0013

p < α ie 0.05

So, H0 is rejected

Hence we state that standard deviation is > 8 miles per hpur

6 0

3 years ago

Slips of paper numbered 1 to 15 are placed in a box. A slip of paper is drawn at random. What is the probability that the number

monitta

Given:

Slips of paper numbered 1 to 15 are placed in a box.

To find:

The probability that the number picked is either a multiple of 5 or an odd number.

Solution:

We have,

Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

No. of total outcomes = 15

Multiple of 5 are 5, 10, 15.

Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.

Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.

No. of favorable outcomes = 9

We know that,

$\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

$\text{Probability}=\dfrac{9}{15}$

$\text{Probability}=\dfrac{3}{5}$

$\text{Probability}=0.6$

Therefore, the probability that the number picked is either a multiple of 5 or an odd number is 0.6.

8 0

3 years ago

Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer

QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0

3 years ago

What is the 100th term of the sequence if the first term is 5<br> and the common difference is 2?

BabaBlast [244]

Answer:

505

Step-by-step explanation:

sn=2a+(n-1)d

2*5+(100-1)5

10+(99)5

505

4 0

3 years ago