Answer:
i think the answer is <u><em>115</em></u>
i am not sure tho..
its not 115
The time taken for the particle to travel more than 8 meters from the point of projection is 0.59 s.
<h3>
Time of motion of the particle</h3>
The time taken for the particle to travel more than 8 meters from the point of projection is calculated as follows;
s = v₀t + ¹/₂at²
8 = 12t + (0.5 x 5)t²
8 = 12t + 2.5t²
2.5t² + 12t - 8 = 0
solve the equation using formula method
t = 0.59 s
Thus, the time taken for the particle to travel more than 8 meters from the point of projection is 0.59 s.
Learn more about time of motion here: brainly.com/question/2364404
Answer: 200
Because for each minute it goes up 200 more.
Answer:
The solution to the system of equations is y = -5 and x = -2.
Step-by-step explanation:
The question tells us to use substitution to solve the system. This means that the given value for x (in terms of y) should be substituted into the other equation. This is modeled below:
-4y - 5x = 30
-4y - 5(y+3) = 30
Next, we should use the distributive property to simplify the left side of the equation.
-4y -5y - 15 = 30
The next step is to combine like terms on the left side of the equation.
-9y - 15 = 30
Then, we can add 15 to both sides of the equation.
-9y = 45
Finally, we can divide both sides of the equation by -9.
y = -5
To find the value for x, we substitute in the value we just found for y into either of our original equations.
x = y + 3
x = -5 + 3
x = -2
Therefore, the correct answer is y = -5 and x = -2.
Hope this helps!
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
