40 boys and 68 girls
let's start with variables and an equation.
boys: x
girls: 2x - 12
and we know that boys and girls make up the class. so let's add the two expressions.
x + 2x - 12 = 108
3x - 12 = 108
+ 12 + 12
3x = 120
x = 40 boys
BUT x is only the number of BOYS in the class. so we have to find girls now. let's plug in our value of x into the girls' equation.
2x - 12 = # of girls
2(40) -12 = # of girls
80 - 12 = # of girls
68 girls
let's check our answer!
68 + 40 does in fact add to 108, therefore our answer is correct.
Geggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg like yuhh
Short answer 34/13Start by converting both to improper fractions.
8 1/2 = (2*8 + 1)/2 = 17/2
3 1/4 = (3*4 + 1)/4 = 13/4
Next set up a 4 layer fraction

Invert the lower fraction and multiply

Cancel the 2 and the 4 leaving you with a 2 in the numerator.
G=11 because the math and the numbers all add one to one round number