Answer:
A quarter of one lap of the track.
Step-by-step explanation:
Three students ran ran a relay and took turns running equal parts of the track.
The race was three-fourths of a lap long.
Let the length of one lap of the track=x
The length of the race
Since each of the students ran equal part,
Length run by each student
Therefore, each student ran a quarter of one lap of the track.
Answer:
The surface area of the given pyramid is 112 .
Step-by-step explanation:
Base length of the pyramid = 4 inches
Area of the base =
=
= 16
Area of its base = 16
Area of one of its triangular surface = x base x height
= x 4 x 12
= 2 x 12
= 24
Area of all its four triangular surfaces = 4 x 24
= 96
surface area of the pyramid = sum of areas of all its surfaces
= 16 + 96
= 112
The surface area of the given pyramid is 112 .
