Answer:
A quarter
of one lap of the track.
Step-by-step explanation:
Three students ran ran a relay and took turns running equal parts of the track.
The race was three-fourths of a lap long.
Let the length of one lap of the track=x
The length of the race
Since each of the students ran equal part,
Length run by each student

Therefore, each student ran a quarter
of one lap of the track.
Answer:
The surface area of the given pyramid is 112
.
Step-by-step explanation:
Base length of the pyramid = 4 inches
Area of the base = 
= 
= 16
Area of its base = 16 
Area of one of its triangular surface =
x base x height
=
x 4 x 12
= 2 x 12
= 24 
Area of all its four triangular surfaces = 4 x 24
= 96 
surface area of the pyramid = sum of areas of all its surfaces
= 16 + 96
= 112 
The surface area of the given pyramid is 112
.
The answer for this would be 10a^5/3
P² + 14p + 40
= p² + 10p + 4p + 40
= p(p+10) + 4(p+10)
= (p+10)(p+4)
Answer:2 and 5
Step-by-step explanation: