A rock is dropped from a height of 64 ft. It is determined that its height (in feet) above ground t seconds later (for 0 ≤ t ≤ 2
1 answer:
Answer:
The average velocity of the rock would be 32 ft per second.
Step-by-step explanation:
A rock has been dropped from a height of 64 ft.
Height of the rock is determined after time 't' by the expression.
S(t) = -16t² + 64
Where 0 ≤ + ≤ 2
Total distance traveled by the rock in
2 seconds = 64 feet
Therefore average velocity = = 32 ft per second
The average velocity of the rock would be 32 ft per second.
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