A rock is dropped from a height of 64 ft. It is determined that its height (in feet) above ground t seconds later (for 0 ≤ t ≤ 2
1 answer:
Answer:
The average velocity of the rock would be 32 ft per second.
Step-by-step explanation:
A rock has been dropped from a height of 64 ft.
Height of the rock is determined after time 't' by the expression.
S(t) = -16t² + 64
Where 0 ≤ + ≤ 2
Total distance traveled by the rock in
2 seconds = 64 feet
Therefore average velocity = = 32 ft per second
The average velocity of the rock would be 32 ft per second.
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Answer: Option a.
Step-by-step explanation:
Make the denominator equal to zero and solve for x:
Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:
Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2
The answer is the option a.
Answer:
Step-by-step explanation:
<u>Firstly we'll factorize the terms:</u>
45x³ = 3 * 3 * 5 * x * x * x
24x² = 2 * 2 * 2 * 3 * x * x
16x = 2 * 2 * 2 * 2 * x
<u>The factor which is common in all three terms is:</u>
= x
Hence GCF = x
Hope this helped!
<h3>~AH1807</h3>