Question

A rock is dropped from a height of 64 ft. It is determined that its height (in feet) above ground t seconds later (for 0 ≤ t ≤ 2) is given by s(t) = -16t²+64. Find the average velocity of the rock over each of the given time intervals. Use this information to guess the instantaneous velocity of the rock at time.

Answer 1

Answer:

The average velocity of the rock would be 32 ft per second.

Step-by-step explanation:

A rock has been dropped from a height of 64 ft.

Height of the rock is determined after time 't' by the expression.

S(t) = -16t² + 64

Where 0 ≤ + ≤ 2

Total distance traveled by the rock in

2 seconds = 64 feet

Therefore average velocity = $\frac{64}{2}$ = 32 ft per second

The average velocity of the rock would be 32 ft per second.