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valentinak56 [21]
2 years ago
5

X^2+y^2=25 is written in polar form as

Mathematics
1 answer:
Wewaii [24]2 years ago
8 0

Answer:

\sqrt{(5+y)(5-y)}  or -\sqrt{(5+y)(5-y)}

Step-by-step explanation:

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Which triangle drfined by the given points on the coordinate plane is similar to the triangle illustrated? ​
Harrizon [31]

Answer:D.) (-1, 1), (-1, 5), (-7, 1)

Step-by-step explanation:The length of the horizontal segment of the triangle graphed is 3.  The length of the vertical segment of the triangle graphed is 2.  Using the Pythagorean theorem, this makes the length of the missing side

2²+3²=c²

4+9 = c²

13=c²

√13 = c

This makes our side lengths 2, 3, and √13.

For choice A our vertices are (-1, 1), (-1, 4), (-6, 1).

This makes the length of the horizontal segment 5 and the length of the vertical segment 3.  This makes the missing side length

5²+3²=c²

25+9=c²

34=c²

√34 = c

This is not proportional to the triangle drawn, so it is not similar.

The vertices of the triangle in option B are (-1, 1), (-1, 5), and (-6, 1).  This makes the horizontal segment 5 units long and the vertical segment 4 units long.  This makes the missing side length

4²+5²=c²

16+25=c²

41=c²

√41=c

These are not proportional to the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice C are (-1, 1), (-1, 4) and (-7, 1).  This makes the length of the horizontal segment 6 and the length of the vertical segment 3.  This makes the missing side length

3²+6²=c²

9+36=c²

45=c²

√45=c

3√5=c

These sides are not proportional to the sides of the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice D are (-1, 1), (-1, 5) and (-7, 1).  This makes the length of the horizontal segment 6 and the length of the vertical segment 4.  This makes the missing side length

6²+4²=c²

36+16=c²

52=c²

√52=c²

2√13=c

These sides are all twice as long as the sides of the triangle drawn; this means the triangles are similar.

4 0
3 years ago
Someone help me with my math homework pleaseee. Find the volumes of the pyramids and the height is 7cm for the first one.
gregori [183]
\bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh\qquad 
\begin{cases}
B=\textit{area of the base}\\
h=height
\end{cases}

now, the first one, on the far-left.... can't see the height.. but I gather you do, now as far as its Base area, well, the bottom is just a 12x12 square, so the area of its base is just 12*12


now, the middle pyramid, has a height of 6, the base is also a square, 8x8, so the Base area is just 8*8

now the last one on the far-right

has a height of 8, the Base is a Hexagon, with sides of 6

\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{4}ns^2cot\left( \frac{180}{n} \right)\qquad 
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of one side}\\
\frac{180}{n}=\textit{angle in degrees}\\
----------\\
n=6\\
s=6
\end{cases}\\\\\\ A=\cfrac{1}{4}\cdot 6\cdot 6^2\cdot cot\left( \frac{180}{6} \right)
5 0
2 years ago
If 3*2=12,3*5=24and 15-6=3then 16/2=?<br>a.4<br>b.6<br>c.8<br>d.12​
ser-zykov [4K]

Answer:

16 divided by 2 equals C which is 8.

Step-by-step explanation:

6 0
3 years ago
V
KATRIN_1 [288]

Answer:

sorry no idea hhcchuucghhf

5 0
2 years ago
An experiment results in one of the sample points upper e 1e1​, upper e 2e2​, upper e 3e3​, upper e 4e4​, or upper e 5e5. comple
ArbitrLikvidat [17]
Given that an experiment results in one of the sample points E1, E2, E3, E4, or E5.

Then P(e1) + P(e2) + P(e3) + P(e4) + P(e5) = 1

If P(E1)=0.1, P(E2)=0.1, P(e4)=0.2, and P(E5)=0.3., then P(E1) = 1 - 0.1 - 0.1 - 0.2 - 0.3 = 0.3

Therefore, P(e3) = 0.3
3 0
3 years ago
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