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Serggg [28]
3 years ago
6

Given that f(x)= x^2-6x and g(x)= x-8 calculate f•g(-2)

Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

9514 1404 393

Answer:

   f•g(-2) = -160

Step-by-step explanation:

f(-2) = (-2)^2 -6(-2) = 4 + 12 = 16

g(-2) = -2 -8 = -10

f•g(-2) =  f(-2)•g(-2) = 16•(-10)

f•g(-2) = -160

Usimov [2.4K]3 years ago
6 0

Answer:

hope this pic helps.enjoy

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dividing both sides by -3 we get:
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The length of a rectangle is 5 meters less than twice the width. If the area of the rectangle is 273 meters, find the dimensions
AleksandrR [38]

The length of the rectangle = 16 meters

The width of the rectangle = 10.5 meters

<u>Step-by-step explanation</u>:

Given that,

The Area of the rectangle is 273.

<u><em>Step 1</em></u><em> :</em>

Let, the width of the rectangle be 'x'

The length of the rectangle is 2x - 5

<u><em>Step 2</em></u><em> :</em>

Area of the rectangle = length \times width

                             273 = (2x - 5) x

                             273 = 2x^2 - 5x

<u><em>Step 3</em></u><em> :</em>

The equation formed is 2x^2 - 5x -273 = 0

a= coefficient of x^2 = 2

b= coefficient of x = -5

c = constant = -273

Find the roots of the equation, to find the width.

<u><em>Step 4</em></u><em> :</em>

Find the roots using factorizing method,

ac = 2\times-273 = -546 and b= -5

Factorizing -546 as -26\times21

The product of -26\times21 = -546

The sum of -26 + 21 = -5

<u><em>Step 5</em></u><em> :</em>

The roots of the equation 2x^2 - 5x -273 = 0 are x= -26/2 and x= 21/2

The values of x are x= -13 and x= 10.5

Since the width cannot be a negative value, neglect x= -13

<u><em>Step 6</em></u><em> :</em>

Therefore,

The width of the rectangle = 10.5 meters

The length of the rectangle = 2x-5

                                                = 2(10.5) - 5

                                                = 21 - 5

                                    length = 16 meters

5 0
3 years ago
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