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3 years ago

Given that f(x)= x^2-6x and g(x)= x-8 calculate f•g(-2)

Mathematics

2 answers:

Nadya [2.5K]3 years ago

7 0

9514 1404 393

Answer:

f•g(-2) = -160

Step-by-step explanation:

f(-2) = (-2)^2 -6(-2) = 4 + 12 = 16

g(-2) = -2 -8 = -10

f•g(-2) = f(-2)•g(-2) = 16•(-10)

f•g(-2) = -160

Usimov [2.4K]3 years ago

6 0

Answer:

hope this pic helps.enjoy

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Graph the image of the given triangle under a dilation with a scale factor of –4 and center of dilation (0,0).

Dvinal [7]

Step-by-step explanation:

Hey there!

The coordinates of a triangle are;

A (1,2)
B (1,-2)
C (-2,-2)
Scale factor = -4 and centre at (0,0)

Now, We have;

P(x,y)----------- P'(kx, ky)

Keep formula;

A(1,2)---------- A'(-4×1 ,-4×2)

= A'(-4, -8)

B(1,-2)------------- B'(-4,8)

C(-2,-2)-------------C'(8,8)

[ The A' should be kept in (-4,-8). There was no place in this graph so, i kept it just below -7. Please while plotting remember to keep it on "-8".]

Hope it helps..

8 0

3 years ago

Solve 3-2cos²x-3sinx=0 for 0≤x≤360

crimeas [40]

3-2(Cosx)^2 - 3Sinx = 0.

Recall (Sinx)^2 + (Cosx)^2 = 1.
Therefore (Cosx)^2 = 1 - (Sinx)^2
Substitute this into the question above.

3-2(Cosx)^2 - 3Sinx = 0
3 - 2(1 - (Sinx)^2) - 3Sinx = 0 Expand
3 - 2 + 2(Sinx)^2 - 3Sinx = 0
1 + 2(Sinx)^2 - 3Sinx = 0 Rearrange
2(Sinx)^2 - 3Sinx + 1 = 0
Let p = Sinx
2p^2 - 3p + 1 = 0 Factorise the quadratic expression
2p^2 - p - 2p +1 = 0
p(2p -1) - 1(2p -1) = 0
(2p-1)(p -1) = 0

Therefore 2p-1=0 or (p-1) = 0
2p=0+1 or (p-1) = 0
2p=1 or p = 0 +1.
p=1/2 or p = 1 Recall p = Sinx

Therefore Sinx = 1/2 or 1.
For 0<x<360

Sinx =1/2, x = Sin inverse (1/2) , x = 30,
 (180-30)- 2nd Quadrant = 150 deg
Sinx = 1, x = Sin inverse (1) , x = 90

Therefore x = 30,90 & 150 degrees.

Cheers.

7 0

3 years ago

After the consumption of an alcoholic beverage, the concentration of alcohol in the bloodstream (blood alcohol concentration, or

bezimeni [28]

Answer:

about 0.177 mg/mL

Step-by-step explanation:

The maximum is found where the derivative of C(t) is zero.

dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0

Solving for t gives ...

t = 1/2.802

So, the maximum C(t) is ...

C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL

The maximum average BAC during the first 6 hours is about 0.177 mg/mL.

_____

The maximum occurs about 21 minutes 25 seconds after consumption.

8 0

2 years ago

Solve the equation for P: 3k=7Q+6p

iren [92.7K]

3k=7Q+6p

Solve for P which means we have to make 'p' alone

$3k=7Q+6p\\\\ Add 7Q on both sides \\\\ 3k - 7Q = 7Q - 7Q + 6p\\\\ \left ( 3k - 7Q \right ) = 6p\\\\ Divide both side by 6 to make p alone \\\\ \frac{\left ( 3k - 7Q \right )}{6} = \frac{6p}{6}\\\\ p = \frac{\left ( 3k - 7Q \right )}{6}$