Answer:
(c) 5/2
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
a^-b = 1/a^b
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Using these rules, we can simplify the expression as follows:
(5^-3)(2^2)(5^6)/((2^3)(5^2)) = (5^(-3+6-2))(2^(2-3)) = (5^1)(2^-1)
= 5/2
For this case we have the following equation of motion:
h (t) = -16t ^ 2 + 90t
Equaling the equation to zero we have:
-16t ^ 2 + 90t = 0
We look for the roots of the polynomial:
(t) (- 16t + 90) = 0
t1 = 0 (initial position)
t2 = 90/16 = 5.625 s (time it reaches the ground again)
Answer:
it will return to the ground in:
t = 5.625 s
Answer:
f(x) = 150-25x
Step-by-step explanation:
200-50=150.
Take the 150 and insert it there.
Each lesson is $25, so you multiply 25 by 2 every lesson. Example= 150-25=125-25=100-75 and so on.
ANSWER:
the answer 130
Step-by-step explanation:
Is greater than or equal to $.00
