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Anton [14]
2 years ago
7

The graph below shows where the two functions y = f(x) and y = g(x) intersect. Solve the equation f(x) = g(x).

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
7 0
Answer: (-2, 2) and (4, 8)

There are two solutions because the two functions cross each other twice.
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Find the approximate side length of a square game board with an area of 123 inches to the second power
aleksklad [387]
61.5 or 61 and one half
4 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
Question is in the picture pls help.
Usimov [2.4K]

Answer:

c. is the answer

5 0
2 years ago
Read 2 more answers
Find the slope of the line that passes through (-2, 8) and (-10, 14)
vesna_86 [32]
Hello!

To find the slope we divide the difference of the y-values by the difference of the x-values as shown below.

\frac{14-8}{-10+2} = -\frac{6}{8} = -\frac{3}{4}

The slope of our line is -3/4.

I hope this helps!
8 0
3 years ago
Read 2 more answers
Please help I don’t know if I’m doing this correctly
solmaris [256]

Answers:

  1. Exponential and increasing
  2. Exponential and decreasing
  3. Linear and decreasing
  4. Linear and increasing
  5. Exponential and increasing

=========================================================

Explanation:

Problems 1, 2, and 5 are exponential functions of the form y = a(b)^x where b is the base of the exponent and 'a' is the starting term (when x=0).

If 0 < b < 1, then the exponential function decreases or decays. Perhaps a classic example would be to study how a certain element decays into something else. The exponential curve goes downhill when moving to the right.

If b > 1, then we have exponential growth or increase. Population models could be one example; though keep in mind that there is a carrying capacity at some point. The exponential curve goes uphill when moving to the right.

In problems 1 and 5, we have b = 2 and b = 1.1 respectively. We can see b > 1 leads to exponential growth. I recommend making either a graph or table of values to see what's going on.

Meanwhile, problem 2 has b = 0.8 to represent exponential decay of 20%. It loses 20% of its value each time x increases by 1.

---------------------

Problems 3 and 4 are linear functions of the form y = mx+b

m = slope

b = y intercept

This b value is not to be confused with the previously mentioned b value used with exponential functions. They're two different things. Unfortunately letters tend to get reused.

If m is positive, then the linear function is said to be increasing. The line goes uphill when moving to the right.

On the other hand if m is negative, then we go downhill while moving to the right. This line is decreasing.

Problem 3 has a negative slope, so it is decreasing. Problem 4 has a positive slope which is increasing.

7 0
1 year ago
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